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3 years ago

What forms the organic portion of soil?

Chemistry

1 answer:

telo118 [61]3 years ago

5 0

Answer:

<h2>Dead & Decaying Organisms</h2>

Explanation:

There are many inorganic components of soil, such as clay. However, soil is mainly comprised of dead and decaying organisms. For example, old, and decaying plants.

PLEASE MARK BRAINLIEST

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How many molecules of C6H6O are there in 1.35 moles of lactic acid

gizmo_the_mogwai [7]

Answer:

4re3

Explanation:

6 0

3 years ago

What are the three hypotheses that were proposed to explain the seismic activity of Pinatubo? What process generates sulfur diox

ASHA 777 [7]

Answer:

Mt. Pinatubo is one of the contrasting volcanoes that erupted violently in the year 1991, being the second strongest volcanic eruption that took place on earth in this entire century.

The 3 hypothesis that was proposed in order to describe the seismic activity of Pinatubo includes-

The magma rising upward to the surface from the interior of the earth, erupting through the crater of the volcano.

The eruption led to the releasing of a large number of volcanic gases into the atmosphere.

The earthquakes are produced due to the continuous tectonic activities that are primarily caused when the earth's crust moves over the layer of viscous asthenosphere.

A large number of volcanic gases are released such as sulfur dioxide (SO₂), methane (CH₄), Hydrogen sulfide (H₂O), Carbon monoxide (CO), and other gases, due to the formation of convection currents and rising up of magma from the mantle, creating volcanic eruptions at the surface

6 0

3 years ago

The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25

sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

$Q=mc\Delta T$

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL = 4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

$Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal$

1 calorie = 4.184 J

$Q=\frac{340,956.75}{4.184} J = 81,490.62 J$

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0

3 years ago

Solve using the correct gas law formula: If the pressure exerted by gas at 25 °C in a constant volume of 3.81 atm, What will the

lilavasa [31]

Answer:

4.31 atm.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and V are constant, and have different values of P and T:

(P₁T₂) = (P₂T₁)

Knowing that:

P₁ = 3.81 atm, T₁ = 25°C + 273 = 298 K,

P₂ = ??? atm, T₂ = 50°C + 273 = 323 K,

Applying in the above equation

(P₁T₂) = (P₂T₁)

∴ P₂ = (P₁T₂)/(T₁) = (3.81 atm)(323 K)/(298 K) = 4.31 atm.

4 0

3 years ago

Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno

melamori03 [73]

1.062 mol/kg.

Step 1. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

Step 2. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

Step 3. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

Step 4. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

Step 5. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

Step 6. Calculate the molal concentration of the NaOH

b = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0

4 years ago