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MakcuM [25]
3 years ago
6

Keplers laws follow which law discovered by sir Isaac Newton

Physics
2 answers:
Zolol [24]3 years ago
8 0

“Universal Gravitational Law” discovered by Sir Issac Newton followed Kepler’s law.

<u>Explanation:</u>

The acceleration of the moon and objects on the earth are compared by Newton. Gravitational force directly depends on both the object's masses and inversely proportional to square of distance between the center of the objects.

Kepler’s Laws of Motion has been reviewed and Newton developed the proof that elliptical form of planetary orbits resulting the centripetal force which is inversely proportional to square of radius vector.

V125BC [204]3 years ago
7 0

The Keplers Laws about the motion of planets leds to Newton to discovered the three laws of motion. Newton based on Kepler came to the conclusion that all motion whereas it was follow the same principle.

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You are moving into an apartment and take the elevator to the 6th floor. Suppose your weight is 790 N and that of your belonging
aliina [53]

Answer:

a) W=26600J

b) W=-12008J

Explanation:

Given the information from the exercise we can calculate the work done by the elevator using the following formula:

W=F*s

a) Considering you and your belongings as a system we know that the elevator is applying a Normal reaction force of:

F=790N+960N=1750N

Since the force applied and the displacement is in the same direction, the work done by the elevator is positive

W=(1750N)(15.2m)=26600J

b) The reaction force applied by the elevator is the same as the weight of the person

F=790N

Since the force applied and the displacement is in opposite direction, the work done by the elevator is negative

W=-(790N)(15.2m)=-12008J

7 0
3 years ago
Consider the collision of a 1500-kg car traveling east at 20.0 m/s (44.7 mph) with a 2000-kg truck traveling north at 25 m/s (55
masha68 [24]

Answer:

1. X_{cm}=-8.57m

2. Y_{cm}=-14.29m

3. V_{cm} = 16.66m/s

4. α = 59.05°

5. V_{cm} = 16.66m/s

6. α = 59.05°

Explanation:

The position of the center of mass 1s before the collision is:

X_{cm}=\frac{X_c*mc+X_t*m_t}{m_c+m_t}

where

X_c=-20m;  m_c=1500kg;  

X_t=0m;   m_t=2000kg;

Replacing these values:

X_{cm}=-8.57m

Y_{cm}=\frac{Y_c*mc+Y_t*m_t}{m_c+m_t}

where

Y_c=0m;  m_c=1500kg;  

Y_t=-25m;   m_t=2000kg;

Replacing these values:

Y_{cm}=-14.29m

The velocity of their center of mass is:

V_{cm-x}=\frac{V_{c-x}*mc+V_{t-x}*m_t}{m_c+m_t}

where

V_{c-x}=20m/s;  m_c=1500kg;  

V_{t-x}=0m/s;   m_t=2000kg;

Replacing these values:

V_{cm-x}=8.57m/s

V_{cm-y}=\frac{V_{c-y}*mc+V_{t-y}*m_t}{m_c+m_t}

where

V_{c-y}=0m;  m_c=1500kg;  

V_{t-y}=-25m;   m_t=2000kg;

Replacing these values:

V_{cm-y}=-14.29m

So, the magnitude of the velocity is:

V_{cm}=\sqrt{V_{cm-x}^2+V_{cm-y}^2}

V_{cm}=16.66m/s

The angle of the velocity is:

\alpha =atan(V_{cm-y}/V_{cm-x})

\alpha=59.05\°

Since on any collision, the velocity of the center of mass is preserved, then the velocity after the collision is the same as the previously calculated value of 16.66m/s at 59.0° due north of east

4 0
3 years ago
Which diagram shows a light ray moving from a more dense into a less dense medium?​
Soloha48 [4]

Answer : it’s A

Explanation:

8 0
2 years ago
46. Can you take a walk in such a way that the distance
Vikki [24]

Answer: In a logical Pace forum subject to the distance

Explanation:

7 0
2 years ago
Which term describes the upward force that acts on an object submerged in a fluid?
MaRussiya [10]
The answer would be: buoyancy


6 0
3 years ago
Read 2 more answers
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