Answer:
Approximately
, assuming that
.
Explanation:
Let
denote the time required for the package to reach the ground. Let
and
denote the initial and final height of this package.
.
For this package:
- Initial height:
. - Final height:
(the package would be on the ground.)
Solve for
, the time required for the package to reach the ground after being released.
.
.
Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at
.) From calculations above, the package would travel forward at that speed for about
. That corresponds to approximately:
.
Hence, the package would land approximately
in front of where the plane released the package.
Here is your answer
Windmill- Wind energy - Mechanical energy- Electrical energy.
Flashlight- Chemical energy- Heat and light energy.
Microwave- Electrical- Thermal energy.
Firecrackers- Chemical- Heat, light and sound.
Bicycle- Muscular energy- Kinetic energy
Battery- Chemical- Electrical energy
Electrical- Thermal
Microwave
Chemical- Thermal
Burning of coal
Electrical- Mechanical
Electric motor
HOPE IT IS USEFUL
Answer:
the <em>ratio F1/F2 = 1/2</em>
the <em>ratio a1/a2 = 1</em>
Explanation:
The force that both satellites experience is:
F1 = G M_e m1 / r² and
F2 = G M_e m2 / r²
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- r is the orbital radius
- M_e is the mass of Earth
Therefore,
F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]
F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]
F1/F2 = m1/m2
F1/F2 = 1000/2000
<em>F1/F2 = 1/2</em>
The other force that the two satellites experience is the centripetal force. Therefore,
F1c = m1 v² / r and
F2c = m2 v² / r
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- v is the orbital velocity
- r is the orbital velocity
Thus,
a1 = v² / r ⇒ v² = r a1 and
a2 = v² / r ⇒ v² = r a2
Therefore,
F1c = m1 a1 r / r = m1 a1
F2c = m2 a2 r / r = m2 a2
In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,
F1 = F1c
G M_e m1 / r² = m1 a1
a1 = G M_e / r²
also
a2 = G M_e / r²
Thus,
a1/a2 = [G M_e / r²] / [G M_e / r²]
<em>a1/a2 = 1</em>
D , since Voltage is one joule per coulomb