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Katen [24]
2 years ago
9

Mark each of the following statementsas true or false. If a statement refers to "two objects"interacting via some force, you are

not to assume that these twoobjects have the same mass.
A. Every force has one and only one 3rd law pair force.
B. The two forces in each pair act in oppositedirections.
C. The two forces in each pair can act on the same object oron different objects.
D. The two forces in each pair may have different physicalorigins (for instance, one of the forces could be due to gravity,and its pair force could be a normal contact force).
E. The two forces of a 3rd law pair always act ondifferent objects.
F. Given that two objects interact via some force, theaccelerations of these two objects have the same magnitude butopposite directions. (Assume no other forces act on eitherobject.)
G. According to Newton's 3rd law, the force on the (smaller)moon due to the (larger) earth is _________
1 greater inmagnitude than, and in the opposite direction from, the force onthe earth due to the moon.
2 greater inmagnitude than, and in the same direction as, the force on theearth due to the moon.
3 equal inmagnitude to, and in the opposite direction from, the force on theearth due to the moon.
4 equal inmagnitude to, and in the same direction as, the force on the earthdue to the moon.
5 smaller inmagnitude than, and in the opposite direction from, the force onthe earth due to the moon.
6 smaller inmagnitude than, and in the same direction as, the force on theearth due to the moon.
Physics
1 answer:
slega [8]2 years ago
8 0

Answer:

Explanation:

A,D,E

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What is the mass of a cart that accelerates at 3.0 m/s if a 0.5 N force is applied?
frozen [14]

The mass of the cart is 0.167 kg

Explanation:

We can solve the problem by using Newton's second law, which states that the net force applied to an object is equal to the product between its mass and its acceleration:

F=ma

where

F is the net force acting on an object

m is its mass

a is its acceleration

For the cart in this problem, we have

F = 0.5 N is the net force applied

a=3.0 m/s^2 is the acceleration

Substituting, we find the mass:

m=\frac{F}{a}=\frac{0.5}{3.0}=0.167 kg

Learn more about Newton's second law:

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2 years ago
What do u think would happen if a car had all its electrical components (such as windscreens wipers,headlights,blinkers,
MrMuchimi

Answer:

If they are connected in series they will share the same current.

Explanation:

The circuits connected in series, share the same current and for each element passes current that flows from one element to another, so when one of these elements is damaged or removed from the circuit the current of the whole circuit is interrupted and no element will work. The attached image shows a circuit connected in series and can be analyzed that the same current flows through each element.

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3 years ago
A spring-loaded toy gun is used to shoot a ball of mass straight up in the air, as shown in the figure. The spring has spring co
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Answer:

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Explanation:

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What is the difference between muscular endurance and muscular strength? A B or C
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Answer:

Muscular endurance is how many times you can move a weight without getting tired.

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3 years ago
You stand on a frictional platform that is rotating at 1.8 rev/s. Your arms are outstretched, and you hold a heavy weight in eac
dusya [7]

Answer:

20.62361 rad/s

489.81804 J

Explanation:

I_i = Initial moment of inertia = 9.3 kgm²

I_f = Final moment of inertia = 5.1 kgm²

\omega_i = Initial angular speed = 1.8 rev/s

\omega_f = Final angular speed

As the angular momentum of the system is conserved

I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_f=\dfrac{I_i\omega_i}{I_f}\\\Rightarrow \omega_f=\dfrac{9.3\times 1.8}{5.1}\\\Rightarrow \omega_f=3.28235\ rev/s=3.28235\times 2\pi=20.62361\ rad/s

The resulting angular speed of the platform is 20.62361 rad/s

Change in kinetic energy is given by

\Delta K=\dfrac{1}{2}(I_f\omega_f^2-I_i\omega_i^2)\\\Rightarrow \Delta K=\dfrac{1}{2}(5.1\times (20.62361)^2-9.3\times (1.8\times 2\pi)^2)\\\Rightarrow \Delta K=489.81804\ J

The change in kinetic energy of the system is 489.81804 J

As the work was done to move the weight in there was an increase in kinetic energy

6 0
3 years ago
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