Pls help this is due today.

A car travels 100 km to the east. If the first half of the distance is driven at 50 km/h and the second half at 100 km/h, what i

Lina20 [59]

First half:

50 km at 50 km/hr ... 1 hour

Second half:

50 km at 100 km/hr ... 1/2 hour

Total distance = 100 km

Total time = 1.5 hours

Average speed = (100 km) / (1.5 hrs)

Average speed = 66 and 2/3 km/hr

Average velocity = 66 and 2/3 km/hr East

8 0

3 years ago

A student is planning an experiment to find

mamaluj [8]

Answer:

b) the height the ball bounces

Explanation:

the control variable is the variable that you change yourself. since you change the height that the ball bounces from we know this is the answer

4 0

3 years ago

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An object that has the ability to do work has __________ energy.

harkovskaia [24]

I believe the correct answer is kinetic energy.

We know that kinetic energy is the movement of any object, no matter its size.

Mechanical energy is a type of kinetic energy, which involves the movement of larger objects.

I hope I helped!

If you need a more thorough explanation, don't hesitate to message me or leave a comment down below.

Here's a video that explains energy:

https://www.khanacademy.org/science/physics/work-and-energy/work-and-energy-tutorial/v/work-and-energy-part-2?modal=1

5 0

3 years ago

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A worker at the top of a 588-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligib

liq [111]

The final velocity of the tool is 107.4 m/s

Explanation:

We can solve this problem by using the principle of conservation of energy.

In fact, if air resistance is negligible, the total mechanical energy of the tool is conserved during the fall, so we can write:

$K_i + U_i = K_f + U_f$

where

$K_i = 0$ is the kinetic energy of the tool at the top (zero since it is at rest)

$U_i = mgh$ is the gravitational potential energy of the tool at the top, where

m is the mass of the tool

g is the acceleration of gravity

h is the heigth of the tool

$K_f = \frac{1}{2}mv^2$ is the kinetic energy of the tool just before hitting the ground, where

v is the final speed of the tool

$U_f = 0$ is the gravitational potential energy of the tool at the bottom (zero since the height is zero)

Re-arranging the equation,

$mgh=\frac{1}{2}mv^2$

where we have

$g=9.8 m/s^2\\h=588 m$

And solving for v,

$v=\sqrt{2gh}=\sqrt{2(9.8)(588)}=107.4 m/s$

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0

3 years ago

Which example does not describe a behavioral adaptation? A. A squirrel buries acorns to dig up and eat later. B. A honeybee does

chubhunter [2.5K]

The answer is B) A honeybee does a dance to tell the other bees where to find flowers.
Honeybees do not dance, first of all.
Second, that is not an adaptation. That is more like a message. An adaptation is changing to the environment to survive. This is not changing to the environment. They are just signaling the other bees.
A, C, and D are all adaptations. They change so that they can survive. They do a different method than usual.
~Deceptiøn

6 0

3 years ago

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