1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hunter-Best [27]
3 years ago
11

A projectile is launched from ground level at an angle of 30 degrees above the horizontal. Neglect air resistance and consider t

he motion from just after the moment it is launched to just before the moment it lands on the ground. When does the projectiles velocity equal its launch velocity?At the highest point.  The projectile's velocity is never equal to its launch velocity after launch.  The projectile's velocity is always equal to its launch velocity.  Just before landing on the ground.  Halfway back to the ground.  Halfway to the highest point. 
Physics
1 answer:
Oduvanchick [21]3 years ago
6 0

Answer:

just before landing the ground

Explanation:

Let the velocity of projection is u and the angle of projection is 30°.

Let T is the time of flight and R is the horizontal distance traveled. As there is no force acting in horizontal direction, so the horizontal velocity remains constant. Let the particle hits the ground with velocity v.

initial horizontal component of velocity, ux = u Cos 30

initial vertical component of velocity, uy = u Sin 30

Time of flight is given by

T = \frac{2u Sin\theta }{g}

Final horizontal component of velocity, vx = ux = u Cos 30

Let vy is teh final vertical component of velocity.

Use first equation of motion

vy = uy - gT

v_{y}=u_{y}- g \times \frac{2u Sin\theta }{g}

v_{y}=u Sin 30 - 2u Sin 30

vy = - u Sin 30

The magnitude of final velocity is given by

v = \sqrt{v_{x}^{2}+v_{y}^{2}}

v = \sqrt{\left (uCos 30  \right )^{2}+\left (uSin 30  \right )^{2}}

v = u

Thus, the velocity is same as it just reaches the ground.

You might be interested in
Three disks are spinning independently on the same axle without friction. Their respective rotational inertias and angular speed
ololo11 [35]

Answer:

3/7 ω

Explanation:

Initial momentum = final momentum

I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet

-Iω + 6Iω - 2Iω = 7I ωnet

3Iω = 7I ωnet

ωnet = 3/7 ω

The final angular velocity will be 3/7 ω counterclockwise.

7 0
3 years ago
Read 2 more answers
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
3 years ago
Read 2 more answers
7.1 Project Guidelines 2021
Ede4ka [16]
I’m not sure if this will help but I found: https://prezi.com/l0fa6du3b9kp/going-off-the-grid-assignment/?fallback=1 and
3 0
2 years ago
The speed of a car during a trip is represented in the graph. Compare distance and displacement at four hours into the trip.
mezya [45]

Answer:

The answer to your question is: D.

Explanation:

Distance refers to the amount of space between two points, it is a scalar quantity.

Displacement refers to the space between two points, measure from the minimum path linking them, it is a vector quantity.

I'm not agree with these answers, because the total distance  is approximately 500km.

A) The distance traveled is 300 km.  This answer is not correct.

B) Distance is 300 km and displacement is 0 km.  This answer is not correct because the displacement is also 500 km.

C) Distance is 300 km/hour and displacement is 300 km. 300 km/h is a measure of speed not of distance, this option is wrong.

D) Both distance traveled and displacement are 300 km. I think this is the correct answer because distance and displacement measure the same. but I think both measure 500 km.

7 0
3 years ago
Read 2 more answers
Q:
Shalnov [3]

Answer:

Explanation:

We will use the KE equation you wrote here and fill in what we are given:

36=\frac{1}{2}m(12)^2 and isolating the m:

m=\frac{2(36)}{12^2} which gives us

m = .50 kg

3 0
3 years ago
Other questions:
  • A 2-kilogram object falls 3 meters. a. How much potential energy did the object have before it fell? b. How much work was accomp
    15·1 answer
  • HELP ASAP!! WILL MARK BRAINLIEST
    15·2 answers
  • What happens to electron flow with a conductor of the voltage source is removed?
    6·1 answer
  • An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
    12·1 answer
  • For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg
    11·1 answer
  • A push on a textbook with 10 N moves it to a distance of 2 cm. How much force is need to move it to 4 cm?
    10·1 answer
  • A snail crawls 300 cm in 1 hour. Calculate the snail's speed in each of the following units. a. centimeters per hour (cm/h) b. c
    10·1 answer
  • The diagram shows the electric field lines around two charges. Based on the field lines, what is the best description of the cha
    14·2 answers
  • How does the direction of acceleration compare with the direction of the net force that produces it
    5·1 answer
  • PLS HELP ASAP (no links)
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!