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Rainbow [258]
3 years ago
5

What is the molarity if 2.00 liters containing 49.0 grams of sodium carbonate [Na2CO3)?

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
5 0

Answer: The molarity of solution is 0.231 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Molar mass of Na_2CO_3 = 2\times 22.99+1\times 12.01+3\times 16.00=105.99

moles of Na_2CO_3 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{49.0g}{105.99g/mol}=0.462mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.462mol}{2.00L}

Molarity=0.231M

Therefore, the molarity of solution is 0.231 M

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