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Lelechka [254]
3 years ago
8

100 POINTS + BRANLIEST

Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer: 45 degrees I think.

Step-by-step explanation: Based off of looks alone, one could conclude that 3x is approximately 0.5 degrees larger than 2x, 2x is approximately 90 degrees, and that x is approximately half of 2x. so based purely off of observation, it appears that x is approximately 45 degrees. you can multiply x by the number by in it in each instance.

x=45, 2x=90, and 3x=135

Please check if you have a protractor.

Triss [41]3 years ago
5 0

Answer:

yay

Step-by-step explanation:

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PLS ANSWER QUICK, HELP AND EXPLAIN
Eduardwww [97]

Answer:

C.

Step-by-step explanation:

5 0
3 years ago
Is y=3x+4 parallel or perpendicular
Sauron [17]

Answer: y=3x+4 is parallel to y=3x+7

Step-by-step explanation:

<h3> The complete exercise is: "Is y=3x+4 parallel, perpendicular or neither to y=3x+7?"</h3><h3 />

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

First, in order to solve this exercise it is important to remember that, by definition:

1. The slopes of parallel lines are equal.

2. The slopes of perpendicular lines are negative reciprocal.

In this case, you have the following line given in the exercise:

 y=3x+4

You can identify that "m" and "b" are:

m=3\\b=4

And the other line provided in the exercise is this one:

y=3x+7

So, you can identify that:

m=3\\b=7

As you can notice, the slopes of both lines are equal; therefore, you can conclude that those lines are parallel.

6 0
3 years ago
Is anybody else here to help me ??​
Akimi4 [234]

Answer:

\cot(x)+\cot(\frac{\pi}{2}-x)

\cot(x)+\tan(x)

\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}

\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]

\csc(x)[\frac{1}{\cos(x)}]

\csc(x)[\sec(x)]

\csc(x)[\csc(\frac{\pi}{2}-x)]

\csc(x)\csc(\frac{\pi}{2}-x)

Step-by-step explanation:

I'm going to use x instead of \theta because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

\cot(x)+\cot(\frac{\pi}{2}-x)

I'm going to use a cofunction identity for the 2nd term.

This is the identity: \tan(x)=\cot(\frac{\pi}{2}-x) I'm going to use there.

\cot(x)+\tan(x)

I'm going to rewrite this in terms of \sin(x) and \cos(x) because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: \frac{\cos(x)}{\sin(x)}=\cot(x) and \frac{\sin(x)}{\cos(x)}=\tan(x)

So we have:

\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}

I'm going to factor out \frac{1}{\sin(x)} because if I do that I will have the \csc(x) factor I see on the right by the reciprocal identity:

\csc(x)=\frac{1}{\sin(x)}

\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show \cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)} is equal to \csc(\frac{\pi}{2}-x).

So since I want one term I'm going to write as a single fraction first:

\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}

Find a common denominator which is \cos(x):

\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}

\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}

\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}

By  the Pythagorean Identity \cos^2(x)+\sin^2(x)=1 I can rewrite the top as 1:

\frac{1}{\cos(x)}

By the quotient identity \sec(x)=\frac{1}{\cos(x)}, I can rewrite this as:

\sec(x)

By the cofunction identity \sec(x)=\csc(x)=(\frac{\pi}{2}-x), we have the second factor of the right hand side:

\csc(\frac{\pi}{2}-x)

Let's just do it all together without all the words now:

\cot(x)+\cot(\frac{\pi}{2}-x)

\cot(x)+\tan(x)

\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}

\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})

\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]

\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]

\csc(x)[\frac{1}{\cos(x)}]

\csc(x)[\sec(x)]

\csc(x)[\csc(\frac{\pi}{2}-x)]

\csc(x)\csc(\frac{\pi}{2}-x)

7 0
3 years ago
How do you subtract fractions with different denominators?
PilotLPTM [1.2K]
Attached the solution and work.

6 0
4 years ago
Given below are lease terms at the local dealership. What is the total cash
Ludmilka [50]

Answer:

$2900

Step-by-step explanation:

• Length of lease = 36 months

• MSRP of the car = $22,750

• Purchase value of the car after lease = $16,900

• Down payment = $1800

• Monthly payment = $425

• Security deposit = $375

• Acquisition fee = $300

The amounts in bold above (last 4 lines) are usually due at signing. Usually there is also sales tax, but that is not mentioned here.

Total due at signing: $1800 + $425 + $375 + $300 = $2900

Answer: $2900

6 0
3 years ago
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