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Readme [11.4K]
3 years ago
12

Two physical pendulums (not simple pendulums) are made from meter sticks that are suspended from the ceiling at one end. The sti

cks are uniform and are identical in all respects, except that one is made of wood (mass=0.36 kg) and the other of metal (mass=0.82 kg) They are set into oscillation and execute simple harmonic motion. Determine the period of (a) the wood pendulum and (b) the metal pendulum
Physics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

a) T = 0.579 s , b)  T = 0.579 s

Explanation:

The great advantage of wave mechanics is that the general equations for different systems are the same, what changes are the physical parameters involved, the equation of motion is

    x = A cos (wt +φ)

Where w is the angular velocity that is this case for being a solid body is

    w = √ (mg d / I)

Where I is the moment of inertia and d the distance to the pivot point

The moment of inertia for a ruler hold one end is

     I = 1/12 M L²

The lost is related to the frequency and is with the angular velocity

     T = 1 / f

    w = 2π f

    w = 2π / T

    T = 2π / w

    T = 2π √ I / mgd

For our case

    d = L

    T = 2π √(1/12 M L²) / M g L)

    T = 2π √(L/(12 g))

a) wood suppose it is one meter long (L = 1m)

     T = 2π √ (1 / (12 9.8))

     T = 0.579 s

b) metal length (L = 1m)

    T = 2pi RA (1 / (12 9.8))

    T = 0.579 s

The period does not depend on mass but on length

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Which statement about work and power correctly describes an automobile race?
miv72 [106K]
Well this question looks like it makes some assumptions.  So assuming that both cars have the same mass and experience the same wind resistance regardless of speed and same internal frictions, then we could say "The car that finishes last has the lowest power".  The reason is that for a given race the cars must overcome losses associated with motion.  Since they all travel the same distance, the amount of work will be the same for both.  This is because work is force times distance.  If the force applied is the same in both cases (identical cars with constant wind resistance) and the distance is the same for both (a fair race track) then W=F·d will be the same.
Power, however, is the work done divided by the time over which it is done.  So for a slower car, time t will be larger.  The power ratio W/t will be smaller for the longer time (slower car).
7 0
4 years ago
Read 2 more answers
One simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching to
yaroslaw [1]

Complete Question:

One simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.5 m/s in 2.24 s, what will be his total time?

Answer:

total time = 6.24 s

Explanation:

Using the equation of motion:

v = u + at

initial speed, u = 0 m/s

v = 11.5 m/s

t = 2.24 s

11.5 = 0 + 2.24a

a = 11.5/2.24

a = 5.13 m/s²

For the total time spent by the sprinter:

s = ut + 0.5at²

100 = 0.5 * 5.13 * t²

t² = 100/2.567

t² = 38.957

t = √38.957

t = 6.24 s

3 0
4 years ago
The rate of change of velocity or speed is known as acceleration. If a car increases it speed form 10 to 20m/s in 2 seconds, the
lisov135 [29]

Answer:

A) 5 m/s/s

Explanation:

<u>Given the following data;</u>

Initial velocity = 10m/s²

Final velocity = 20m/s²

Time, t = 2 seconds.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration, a = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation, we have;

Acceleration, a = \frac{20 - 10}{2}

Acceleration, a = \frac{10}{2}

<em>Acceleration, a = 5m/s²</em>

7 0
3 years ago
During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.
lord [1]

Answer:

(a) F_{sm} = 4.327\times 10^{20}\ N

(b) F_{em} = 1.983\times 10^{20}\ N

(c) F_{se} = 3.521\times 10^{20}\ N

Solution:

As per the question:

Mass of Earth, M_{e} = 5.972\times 10^{24}\ kg

Mass of Moon, M_{m} = 7.34\times 10^{22}\ kg

Mass of Sun, M_{s} = 1.989\times 10^{30}\ kg

Distance between the earth and the moon, R_{em} = 3.84\times 10^{8}\ m

Distance between the earth and the sun, R_{es} = 1.5\times 10^{11}\ m

Distance between the sun and the moon, R_{sm} =  1.5\times 10^{11}\ m

Now,

We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:

F_{G} = \frac{Gmm'_{2}}{r^{2}}                             (1)

Now,

(a) The force exerted by the Sun on the Moon is given by eqn (1):

F_{sm} = \frac{GM_{s}M_{m}}{R_{sm}^{2}}

F_{sm} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 7.34\times 10^{22}}{(1.5\times 10^{11})^{2}}

F_{sm} = 4.327\times 10^{20}\ N

(b) The force exerted by the Earth on the Moon is given by eqn (1):

F_{em} = \frac{GM_{s}M_{m}}{R_{em}^{2}}

F_{em} = \frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}\times 7.34\times 10^{22}}{(3.84\times 10^{8})^{2}}

F_{em} = 1.983\times 10^{20}\ N

(c) The force exerted by the Sun on the Earth is given by eqn (1):

F_{se} = \frac{GM_{s}M_{m}}{R_{es}^{2}}

F_{se} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 5.972\times 10^{24}}{((1.5\times 10^{11}))^{2}}

F_{se} = 3.521\times 10^{20}\ N

7 0
3 years ago
An Olympic-class sprinter starts a race with an acceleration of 5.10 m/s2. What is her speed 2.40 s later?
ivolga24 [154]

Answer:

12.24 m/s

Explanation:

Speed: This can be defined as the rate of change of distance with time. The S.I unit of speed is m/s.

Using the formula,

a = v/t................ Equation 1

Where a = acceleration of the sprinter, v = speed of the sprinter, t = time.

making v the subject of the equation,

v = at ................. Equation 2

Given: a = 5.1 m/s², t = 2.4 s.

Substitute into equation 2

v = 5.1(2.4)

v = 12.24 m/s.

Hence, the speed of the sprinter = 12.24 m/s

3 0
3 years ago
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