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almond37 [142]
2 years ago
5

An octopus propels itself through the water by ejecting water through a funnel in its body. How does this demonstrate Newton’s t

hird law?(1 point)
When the octopus ejects the water out, the water acts with an equal force on the surrounding water in the same direction.

When the octopus ejects the water out, the water acts with an equal force on the octopus in the same direction.

When the octopus ejects the water out, the water acts with an equal force on the octopus in the opposite direction.

When the octopus ejects the water out, the water acts with an equal force on the surrounding water in the opposite direction.
Physics
2 answers:
valina [46]2 years ago
8 0

Answer: The answer would be C. When Octopus eject the water out, the water acts with an equal force on the octopus in opposite direction.

Explanation:

An octopus propels itself forward in the water by ejecting water backward through a funnel in its body.

Hope this helps! :D

Molodets [167]2 years ago
6 0

Answer:

The first one good luck

Explanation:

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A double-slit arrangement produces interference fringes for sodium light (λ = 589 nm) that are 0.48° apart. What is the angular
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Answer:

0.38°

Explanation:

\theta = Angle

m = Number

d = Distance

n = Refractive index of liquid = 1.25

a denotes air

l denotes liquid

In the case of double split interferance we have the relation

m\lambda=dsin\theta

For air

m\lambda_a=dsin\theta_a

For liquid

m\lambda_l=dsin\theta_l

Dividing the two equations

\frac{m\lambda_a}{m\lambda_l}=\frac{dsin\theta_a}{dsin\theta_l}\\\Rightarrow \frac{\lambda_a}{\lambda_l}=\frac{sin\theta_a}{sin\theta_l}

Wavelength ratio = n

n=\frac{sin\theta_a}{sin\theta_l}\\\Rightarrow \frac{sin0.48}{1.25}=sin\theta_l\\\Rightarrow \theta_l=sin^{-1}\frac{sin0.48}{1.25}\\\Rightarrow \theta_l=0.38^{\circ}

The angular separation is 0.38°

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3 years ago
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Answer:

. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation.

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Answer:

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Explanation:

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