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NNADVOKAT [17]
3 years ago
6

When a bat strikes a ball, the force exerted can send the ball deep into the outfield. Where is the equal and opposite force in

this case? Select one: A. bat's force on the batter B. ball's force on the bat C. ball's force on the air
Physics
1 answer:
Delvig [45]3 years ago
3 0

Answer:

The answer is option B:  the ball´s force on the bat

Explanation:

Using Newton's third law (action and reaction) that says: If two bodies interact the force of one exerts on the other is of equal magnitude, direction and opposite direction

Therefore, if the bat hits the ball (action), the ball (reaction) with a force on the bat of equal magnitude, but opposite direction

You might be interested in
Whenever possible, these types of power plants should be built because they generate virtually no pollution. (2 points)
geniusboy [140]
Wind farms, solar collectors, and nuclear power plants generate no pollution.

But wind farms make noise, wind and solar are both hazardous to birds, and there's no known means of disposing of nuclear plant waste that's completely safe.
8 0
3 years ago
1. You place an object 63 cm in front of a converging lens, with a 40 cm focal length.
NikAS [45]

Answer:

1.

109.6 cm ,  - 1.74 , real

2.

1.5

Explanation:

1.

d₀ = object distance = 63 cm

f = focal length of the lens = 40 cm

d = image distance = ?

using the lens equation

\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d}

\frac{1}{40} = \frac{1}{63} + \frac{1}{d}

d = 109.6 cm

magnification is given as

m = \frac{-d}{d_{o}}

m = \frac{-109.6}{63}

m = - 1.74

The image is real

2

d₀ = object distance = a

d = image distance = - (a + 5)

f = focal length of lens = 30 cm

using the lens equation

\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d}

\frac{1}{30} = \frac{1}{a} + \frac{1}{- (a + 5)}

a = 10

magnification is given as

m = \frac{-d}{d_{o}}

m = \frac{- (- (a +5))}{a}

m = \frac{(5 + 10)}{10}

m = 1.5

6 0
3 years ago
Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2
lbvjy [14]
-- The car starts from rest, and goes 8 m/s faster every second.

-- After 30 seconds, it's going (30 x 8) = 240 m/s.

-- Its average speed during that 30 sec is  (1/2) (0 + 240) = 120 m/s

-- Distance covered in 30 sec at an average speed of 120 m/s 

                                                                           = <span> 3,600 meters .</span>
___________________________________

The formula that has all of this in it is the formula for 
distance covered when accelerating from rest:

       Distance = (1/2) · (acceleration) · (time)²

                       = (1/2) ·      (8 m/s²)     · (30 sec)²

                       =      (4 m/s²)          ·      (900 sec²)

                       =            3600 meters.

_________________________________

When you translate these numbers into units for which
we have an intuitive feeling, you find that this problem is 
quite bogus, but entertaining nonetheless.

When the light turns green, Andy mashes the pedal to the metal
and covers almost 2.25 miles in 30 seconds. 

How does he do that ?

By accelerating at 8 m/s².  That's about 0.82 G  !

He does zero to 60 mph in 3.4 seconds, and at the end
of the 30 seconds, he's moving at 534 mph !  

He doesn't need to worry about getting a speeding ticket.
Police cars and helicopters can't go that fast, and his local
police department doesn't have a jet fighter plane to chase
cars with. 
5 0
3 years ago
This diagram shows two different forces acting on a skateboarder. The
ludmilkaskok [199]

Answer:

B

Explanation:

7 0
3 years ago
You are running at a speed of 10km/h and hit a patch of mud. Two seconds later you speed is 8km/h. What is your acceleration in
Vlad1618 [11]

Answer:

0.28 m/s^2

Explanation:

Acceleration is given by

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time interval

In this problem:

u = 10 km/h \cdot \frac{1000 m/km}{3600 s/h}=2.78 m/s is the initial velocity

v = 8 km/h \cdot \frac{1000 m/km}{3600 s/h}= 2.22 m/s is the final velocity

t = 2 s is the time

Substituting, we find the acceleration:

a=\frac{2.78-2.22}{2}=0.28 m/s^2

5 0
3 years ago
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