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Ne4ueva [31]
3 years ago
7

Question 3

Chemistry
2 answers:
meriva3 years ago
8 0

Answer:

We are dependent on plants and plants need CO2 from enviromen

Explanation:

Liono4ka [1.6K]3 years ago
3 0

Answer:

These are necessary for breathing, drinking etc.

Even they are basic components of our body such as present in DNA etc.

#$#THANK YOU #$#

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If you stay at 90 degrees Celsius and a gas in a liquid solution has a pressure of 2 atm, what solubility should it have if it h
grigory [225]

Answer:

im not sure

Explanation:

5 0
3 years ago
What is the molar mass of CaCl2?
alekssr [168]
Molar mass of CaCl2 = 40+ ( 35.5 ×2)=110

Mr of Ca(OH)2 = 40+ (16+1)×2 =74

%of Ca = (40÷ 74)×10=...

1 m = 100cm...
1cm = (1÷100) m
So 45.5 cm = 45.5 ×(1÷100) =....

1km = 1000m
1m = 100 cm
1cm =10mm
So 1km = 1000×100×10 mm
Now convert
7 0
3 years ago
Determine the mass of 5.20 moles of c6h12
Gwar [14]
Mass is equal to moles x molar mass, and the molar mass of C6H12 is 84, therefore the mass is 436.8 g, but 437 rounded to correct significant figures
5 0
3 years ago
What does the rf value describe on a microscopic level why is this important?
lys-0071 [83]

Answer: The retention factor describes the rate at which a compound migrates on a microscopic level.

The retention factor (Value) serves as a simple measurement of the relative binding of the compound of interest under the experimental conditions.

Retention factor values are used in identification purposes;

• Use to determine the affinity of the solute to the solvent

• Greater retention factor means greater affinity of solute to the solvent

Explanation:

8 0
3 years ago
An aluminum kettle weights 1.05 kg and has a heat capacity of 0.9211 J over grams Celsius how much heat is required to increase
Serggg [28]

Answer:

64799.4 J

Explanation:

The following data were obtained from the question:

Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g

Specific heat capacity (C) = 0.9211 J/g°C

Initial temperature (T1) = 23°C

Final temperature (T2) = 90°C

Change in temperature (ΔT) = T2 – T1 =

90°C – 23°C = 67°C

Heat required (Q) =....?

The heat required to increase the temperature of the kettle can b obtain as follow:

Q = MCΔT

Q = 1050 x 0.9211 x 67

Q = 64799.4 J

Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.

4 0
3 years ago
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