Ask question

Ask question

All categories

2 years ago

7

Question 3

2 answers:

meriva2 years ago

8 0

Answer:

We are dependent on plants and plants need CO2 from enviromen

Explanation:

Liono4ka [1.6K]2 years ago

3 0

Answer:

These are necessary for breathing, drinking etc.

Even they are basic components of our body such as present in DNA etc.

#$#THANK YOU #$#

You might be interested in

The proof that ch4 is a weak acid

boyakko [2]

Answer: because ch4 is not considered a acid they said it is too weak

Explanation:

8 0

3 years ago

Read 2 more answers

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

2 years ago

How many moles of oxygen are in 1 mole of Fe(NO3)3?

goldfiish [28.3K]

<span> There are 97.2 mol of O in 10.8 mol of Fe(NO3)3</span>

7 0

2 years ago

Can anyone answer this? (I thank)

Mamont248 [21]

CO2 will be the first to boil because it will be the first to warm up because it is the closest temperature to 0

4 0

2 years ago

What is another name for groups of elements?

jeka94

They are called groups or family. Hope this helps

6 0

2 years ago