Answer:
It’s b even check quizzes
Explanation:
Respuesta:
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)
Explicación:
Consideremos la ecuación no balanceada que ocurre cuando cloruro férrico acuoso reacciona con carbonato de sodio sólido para formar carbonato férrico sólido y cloruro de sodio acuoso. Esta es una reacción de doble desplazamiento.
FeCl₃(aq) + Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Vamos a usar el método de tanteo. Empezaremos balanceando los átomos de C, multiplicando Na₂CO₃ por 3.
FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Luego, balancearemos los átomos de Fe, multiplicando FeCl₃ por 2.
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + NaCl(aq)
Finalmente, obtendremos la ecuación balanceada, multiplicando NaCl por 6.
2 FeCl₃(aq) + 3 Na₂CO₃(s) ⇒ Fe₂(CO₃)₃(s) + 6 NaCl(aq)
Actual Resources: are those which have been surveyed, their quantity and quality determined and are being used in present times.
Potential Resources: <span>They can exist in a region and can be used in the future.</span>
Answer:
C Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)
Explanation:
In order to determine the correct rate law, let's use Trial 1 as baseline. Therefore:
An increase in [A] in Trial 2 by a factor of
leads to an increase in the rate of reaction by a factor of 2 (i.e. the reaction rate is doubled). Thus, there is second order in [A].
Similarly,
An increase in [B] in Trial 3 by a factor of 1.667 leads to an increase in the rate of reaction by a factor of 1.667. Thus, there is first order in [B].
Futhermore,
An increase in [C] in Trial 4 by a factor of 1.71 leads to a decrease in the rate of reaction by 1.71. Thus, there is inverse first order in [C].
Therefore, the correct rate law is:
Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)