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ololo11 [35]
2 years ago
5

Rank the following series of molecules or ions in order of decreasing bond energy using their bond order to predict relative mag

nitude: chlorine: Cl2, sulfur: S2, phosphorus: P2.
Chemistry
1 answer:
Mars2501 [29]2 years ago
4 0

Answer:

P2>S2>Cl2 is the order of bond energy of the given molecules.

Explanation:

The bonding in each molecule is shown below:

Thus, between each P-atom, there exists a triple bond.

Between two S-atoms there exists a double bond.

Between two chlorine atoms, there exists a single bond.

As the number of bonds increases between the given atoms, then bond energy required to break the bonds also increases.

Thus, the bond order is shown below:

P_2>S_2>Cl_2.

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Number of moles of NaOH = V(NaOH) * M(NaOH)= 0.150 L * 0.1 moles/L = 0.015 moles

Number of moles of formic acid, HCOOH = V(HCOOH) * M(HCOOH) = 0.200 L * 0.1 moles/L = 0.020 moles

Here, the limiting reagent is NaOH

The reaction is represented as:

HCOOH + NaOH ↔HCOONa + H2O

Moles of HCOONa formed = Moles of the limiting reagent, NaOH = 0.015 moles

Moles of HCOOH remaining = 0.020-0.015 = 0.005 moles

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Therefore: [HCOOH] = 0.005 moles/1 L = 0.005 M

[HCOONa] = 0.015/1 = 0.015 M

pKa of HCOOH = 3.74

As per Henderson-Hasselbalch equation

pH = pka + log[HCOONa]/[HCOOH] = 3.74+log[0.015/0.005] = 4.22

Therefore, pH of the final solution = 4.22


                       


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