All categories

3 years ago

What are properties ?

Chemistry

1 answer:

frozen [14]3 years ago

8 0

Answer:

Explanation:

In logic and philosophy, a property is a characteristic of an object; a red object is said to have the property of redness. The property may be considered a form of object in its own right, able to possess other properties.

You might be interested in

If the atom is assumed to be a sphere, what is the volume in cm3 of a single copper (cu) atom?

kompoz [17]

Atomic radius of copper atom (r)= 128 pm

volume of sphere = 4/3 * pi * r^3 = 4/3 * 3.14 * 128^3

volume = 8780076.373 pm^3

5 0

3 years ago

Calculate the number of atoms of bromine in 1.37 g of bromine. Give your answer in scientific notation. Enter your answer in the

steposvetlana [31]

Answer: The number of atoms of bromine present in given number of mass is $1.03\times 10^{22}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of bromine = 1.37 g

Molar mass of bromine = 79.904 g/mol

Putting values in above equation, we get:

$\text{Moles of bromine}=\frac{1.37g}{79.904g/mol}=0.0171mol$

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of atoms.

So, 0.0171 moles of bromine will contain = $0.0171\times 6.022\times 10^{23}=1.03\times 10^{22}$ number of bromine atoms.

Hence, the number of atoms of bromine present in given number of mass is $1.03\times 10^{22}$

4 0

3 years ago

A certain first-order reaction has a rate constant of 2.75 10-2 s−1 at 20.°c. what is the value of k at 45°c if ea = 75.5 kj/mol

Gekata [30.6K]

Answer:

0.314 s⁻¹

Step-by-step explanation:

Use the Arrhenius equation.

$\ln( \frac{k_2 }{k_1 }) = (\frac{E_{a} }{R })(\frac{ 1}{T_1} - \frac{1 }{T_2 })\\$

Data:

k₁ = 0.0275 s⁻¹; k₂ = ?

Eₐ = 75.5 kJ·mol⁻¹

T₁ = 20 °C = 293.15 K; T₂ = 45°C = 318.15 K

Calculation:

$\ln(\frac{k_{2} }{0.0275}) = (\frac{75 500 }{8.314})(\frac{ 1}{293.15} - \frac{1 }{318.15 })$

$\ln(\frac{k_{2} }{0.0275}) = 9081\times 2.681 \times10^{-4}$

$\ln(\frac{k_{2} }{0.0275}) = 2.434$

$\frac{k_{2} }{0.0275} = \text{e}^{2.434}$

$\frac{k_{2} }{0.0275} = 11.41$

k₂ = 0.0275 × 11.41

k₂ = 0.314 s⁻¹

3 0

3 years ago

The system of electrons surrounding the nucleus of an atom

Mashutka [201]

Shielding electrons

5 0

3 years ago

Write a balanced nuclear equation for the beta decay of protactinium

PSYCHO15rus [73]

$_{91}^{231}Pa --\ \textgreater \ _{92}^{231}U + _{-1}^{0}e$

7 0

3 years ago