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2 years ago

How could you increase the kinetic Energy of an object without changing its mass or gravity? *

Physics

1 answer:

lara [203]2 years ago

8 0

Answer: Height

Explanation:

You could raise it further off the ground.

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V=I/R correctly expresses the relationship between voltage, current, and resistance.

docker41 [41]

The correct answer is true

5 0

1 year ago

Read 2 more answers

A capacitor is charged until it holds 5.0 j of energy. it is then connected across a 10-kω resistor. in 13.6 ms , the resistor d

prohojiy [21]

Answer:

The capacite is C=5.32 uF using the equations of voltage and energy in capacitance

Explanation:

The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J

Using:

$V_{t}= V_{o}e^{\frac{-t}{R*C} }$

Voltage in this case is the energy dissipated so

$E_{t}= E_{o}e^{\frac{-t}{R*C} }$

$\frac{\sqrt{E_t} }{\sqrt{E_o} } = e^{\frac{-t}{R*C} }$

$\frac{\sqrt{3 J} }{\sqrt{5J} } = e^{\frac{-13.6ms}{10kw*C} }$

Using the equation to find capacitance

$ln 0.775= e^{\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\ln(0.775)= ln * e^{\frac{-13.6 x10^{3s} }{10x10^{3}*C }} \\\\ln(0.775)= {\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\C= \frac{-13.6 x10^{-3} }{10x10x^{3}*ln(0.775) }$

$C= 5.32x10^{-6}$ F

C= 5.32 uF because u is the symbol for micro that is equal to $10^{-6}$

8 0

3 years ago

An electric light is plugged into a 120-V outlet. If the current in the bulb is 0.50 A, how much electrical energy does the bulb

ioda

Answer:

= 54,000 Joules or 54 kJ

Explanation:

Electrical energy is given by the formula;

E = VIt; where V is the potential difference in volts, I is the current and t is the time in seconds.

Therefore;

Electrical energy = 120 V × 0.50 A × 15 ×60 seconds

= 54,000 Joules

Thus; the electrical energy is 54,000 joules or 54 kJ

7 0

2 years ago

Choose the nonmetallic elements from the list. Check all that apply.

NikAS [45]

Polonium, gallium,argon

3 0

3 years ago

Read 2 more answers

Un niño amarra una soga a una piedra, y la hace girar como en la gráfica. la piedra realiza un M.C.U, girando con una rapidez de

inessss [21]

Answer:

$\Delta \theta = 56\,rad$

$\Delta \theta \approx 3208.564^{\circ}$

Explanation:

El ángulo barrido en el intervalo de tiempo dado es (The covered angle in the given time interval is):

$\Delta \theta = \omega \cdot \Delta t$

$\Delta \theta = \left(14\,\frac{rad}{s} \rjght)\cdot (4\,s)$

$\Delta \theta = 56\,rad$

$\Delta \theta \approx 3208.564^{\circ}$

4 0

3 years ago