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Varvara68 [4.7K]
3 years ago
12

Which statement explains how weight is different from mass?

Physics
2 answers:
Leviafan [203]3 years ago
5 0

Answer:

weight is always greater than mass, weight is a measure of gravitational pull

Explanation:

Weight=mass x acceleration due to gravity

Therefore weight is always greater than mass. And weight is a measure of gravitational pull

Gennadij [26K]3 years ago
3 0

Answer:

D. Weight is a measure of gravitational pull.

Explanation:

on edgenuity 2020 :))

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A disk of radius 10 cm speeds up from rest. It turns 60 radians reaching an angular velocity of 15 rad/s. What was the angular a
Kruka [31]

Answer: α = 1.875 rad/s²

Explanation:

ω₁² = ω₀² + 2αθ

ω₀ = 0

α = ω₁² / 2θ

α = 15² / 2(60)

α = 1.875 rad/s²

3 0
3 years ago
Calcula qué tan lejos está Saturno del Sol, sabiendo que la luz solar necesita una hora y veinte segundos para llegar a Saturno.
Ksju [112]

Answer:

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3 years ago
Which BEST describes the difference between speed and velocity?
Murljashka [212]
D. velocity includes rate of change and direction

8 0
3 years ago
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A dog has a mass of 20 kg. If the dog is pushed across the ice with a force of 40 N, what is its acceleration?
olasank [31]

Answer:

The acceleration is 2 m/s2.

Explanation:

We calculate the acceleration (a), with the data of mass (m) and force (F), through the formula:

F = m x a  ---> a= F/m

a = 40 N/20 kg                   <em>  1N= 1 kg x m/s2</em>

a= 40 kgx m/s2/ 20 kg

<em>a= 2 m/s2</em>

7 0
3 years ago
A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m
elena-14-01-66 [18.8K]

Answer:

  • <u><em>1,230N</em></u>

Explanation:

<u>1. Name of the variables:</u>

   f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration

<u>2. Formulae:</u>

         f=\dfrac{number\text{ }of\text{ }revolutions}{time}

          \omega=2\pi f

          a_c=\omega^2 r

           F_c=m\times a_c

<u>3. Solution (calculations)</u>

       f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}

       \omega=2\pi\times0.\overline{60}\approx 3.808rad/s

      a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2

      F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N

3 0
3 years ago
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