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Varvara68 [4.7K]
3 years ago
12

Which statement explains how weight is different from mass?

Physics
2 answers:
Leviafan [203]3 years ago
5 0

Answer:

weight is always greater than mass, weight is a measure of gravitational pull

Explanation:

Weight=mass x acceleration due to gravity

Therefore weight is always greater than mass. And weight is a measure of gravitational pull

Gennadij [26K]3 years ago
3 0

Answer:

D. Weight is a measure of gravitational pull.

Explanation:

on edgenuity 2020 :))

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what kind of weather would u assosiate with higher perssure system? How does the density, humidity and air motion compare to tha
expeople1 [14]

Answer:

Low pressure systems typically arrive with storms and clouds. Air motion is usually upwards, as heated are is less dense and more buoyant than cooler air. A high pressure system is typically cooler than its counter-part, and skies are usually clear. Low pressure systems carry more water vapor due to rising hot air cooling and condensing.

4 0
3 years ago
A truck moves 70 m east, then moves 120 m west, and finally moves east again a distance of 90 m. If east is chosen as the positi
asambeis [7]

Answer:

140m east

Explanation:

If East is positive then lets rephrase the problem into integers

A truck moves +70 m, then moves -120m, and finally moves +90m.

So totally Displacement = +70-120+90= +140m

Since east is positive, the trucks resultant displacement is 140 m east of origin

6 0
3 years ago
Please help, it's an exam ://
LenaWriter [7]

Answer:

Whats the question

Explanation:

7 0
3 years ago
The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting
Monica [59]
Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. </span><span>The equation for </span>gravitational potential energy<span> is GPE = mgh. 

GPE = 1200(1.6)(350) = 672000 J

Hope this answers the question. Have a nice day.</span>
8 0
3 years ago
Read 2 more answers
suppose that you had an ohmmeter and a mystery component that could be either an inductor or a capacitor. How could you use the
sukhopar [10]

Answer:

To determine the mystery component we will connect the mystery component to a DC voltage source, then I will measure the resistance of the component with the use of Ohmmeter, the value of the resistance of the mystery component will determine what the mystery component is

if the resistance > 1( very high )   then component is a capacitor

if the resistance = 0 then component is an inductor

Explanation:

To determine the mystery component we will connect the mystery component to a DC voltage source, then I will measure the resistance of the component with the use of Ohmmeter, the value of the resistance of the mystery component will determine what the mystery component is

if the resistance > 1( very high )   then component is a capacitor

if the resistance = 0 then component is an inductor

8 0
3 years ago
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