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labwork [276]
3 years ago
13

A worker with spikes on his shoes pulls on rope that is attached to a box that is resting on a flat, frictionless frozen lake. T

he box has mass m, and the worker pulls with a constant tension T at an angle θ = 30° above the horizontal. Draw a free-body diagram for this system, assuming that the box moves to the right.

Physics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

The drawing of the free-body diagram is shown in the attachment.

Explanation:

In order to draw a free-body diagram for the given situation, you have to include in the drawing of the box all the forces acting in the box, in the correct directions.

The forces involved are:

The weight force (Let W represent it). This force is produced by the gravity force on the box, its direction is perperdicular to the ground, pointing down.

The normal force (Let N represent it). This force is produced by the contact force that the frozen lake applies to the box, its direction is perperdicular to the lake, pointing up.

The tension force (Let T represent it). This force is produced by the worker, who is pulling the rope. Its direction forms  30° above the horizontal, pointing to the right (because the box moves to right)

Notice that there isn't a friction force because the lake is frictionless. Also notice that the tension produces the movement of the box to the right.

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Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the
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Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

Explanation:

The new distance is

\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}

The force can be calculated by the formula

F=k\frac{q1q2}{(r^{\prime})^2}

Here, k is the constant whose value is

k=9\times10^9\text{ N m}^2\text{ /C}^2

On substituting the values, the force will be

\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}

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2 years ago
A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc
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Answer:

Time period of the osculation will be 0.0671 sec  

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So kx=mg

k\times 0.04=0.012\times 9.8

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

T=2\pi \sqrt{\frac{m}{k}}

=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec

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3 years ago
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Answer:

Heat conductivity: Physical property

Silver tarnishing: chemical change

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Length of a metal object: physical property

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exploding dynamite: chemical change

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Acid resistance: chemical property

brittleness: physical property

milk souring: chemical change

baking bread: chemical change

Explanation:

First you need to understand the differences between physical and chemical change; physical and chemical property.

<u>Physical properties vs chemical properties:</u>

Physical properties are properties that you can observe without changing the substance's composition. This means you can measure these properties without changing them chemically.

Chemical properties, on the other hand, are properties are not as direct. These properties are generally determined by the way the react with other substances changing their composition.

<u>Physical changes vs chemical changes:</u>

A substance that undergoes physical change does not change in chemical composition. They may look physically different in terms of size and shape, but overall, their chemical composition remains constant. The best example would be water. Water can change phases, from solid to liquid when they melt. Essentially, they look like different substances, but the change is only physical and not chemical.

Chemical change, is different by the fact that they change in chemical composition. Bonds are broken and/or made through the reaction, which changes them not only physically but chemically as well. Some of the most indicative signs of a chemical change occurring are: change in color, odor, production of gas, production of light/heat.

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