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4 years ago

MATHPHYS PLEASE HELP

Physics

2 answers:

solmaris [256]4 years ago

3 0

Explanation:

Momentum is mass times speed.

p = mv

a) p = (1500 kg) (25.0 m/s) = 37,500 kg m/s

b) p = (40,000 kg) (1.00 m/s) = 40,000 kg m/s

The truck has more linear momentum.

Momentum in the y direction:

pᵧ = (1500 kg) (25.0 m/s) = 37,500 kg m/s

Momentum in the x direction:

pₓ = (1500 kg) (15.0 m/s) = 22,500 kg m/s

Total linear momentum:

p² = pₓ² + pᵧ²

p² = (22,500 kg m/s)² + (37,500 kg m/s)²

p = 43,700 kg m/s

nata0808 [166]4 years ago

3 0

Answer:

p = 43,700 kg m/s

Explanation:

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You are fixing a transformer for a toy truck that uses an 8.0-V emf to run it. The primary coil of the transformer is broken; th

Art [367]

Answer:

a. The primary turns is 60 turns

b. The secondary voltage will be 360 volts.

Explanation:

Given data

secondary turns N2= 40 turns

primary turns N1= ?

primary voltage V1= 120 volts

secondary voltage V2= 8 volts

Applying the transformer formula which is

$\frac{N1}{N2} =\frac{V1}{V2}$

we can solve for N1 by substituting into the equation above

$\frac{N1}{40} =\frac{120}{8} \\\ N1= \frac{40*120}{8} \\\ N1= \frac{4800}{8} \\\ N1= 60$

the primary turns is 60 turns

If the primary voltage is V1 240 volts hence the secondary voltage V2 will be (to get the voltage of the secondary coil using emf substitute the values of the previously gotten N1 and N2 using V1 as 240 volts)

$\frac{40}{60} =\frac{240}{V2}\\\\V2= \frac{60*240}{40} \\\\V2=\frac{ 14400}{40} \\\\V2= 360$

the secondary voltage will be 360 volts.

6 0

3 years ago

The moment of inertia of a thin ring of mass M and radius R about its symmetry axis is ICM = MR2.

monitta

Answer:

The moment of inertia of large ring is 2MR².

(A) is correct option.

Explanation:

Given that,

Mass of ring = M

Radius of ring = R

Moment of inertia of a thin ring = MR²

Moment of inertia :

Moment of inertia is the product of the mass of the ring and square of radius of the ring.

We need to calculate the moment of inertia of large ring

Using formula of moment of inertia

$I=I_{cm}+MR^2$

Where, $I_{cm}$ = moment of inertia at center of mass

M = mass of ring

R = radius of ring

Put the value into the formula

$I=MR^2+MR^2$

$I=2MR^2$

Hence, The moment of inertia of large ring is 2MR².

6 0

3 years ago

A parallel-plate capacitor is charged by a 14.0 V battery, then the battery is removed. You may want to review (Pages 692 - 695)

Anika [276]

Answer:

Potential Difference = 14 V

Explanation:

We are told that when the capacitor plates are charged to a certain voltage, then we have;

ΔV = 14 volts

Now, the battery is disconnected, so here we have the potential difference between the plates to be given by the formula;

ΔV = Q/C

Now, the charge is conserved on the plates and the capacitance is constant, therefore in this case, the potential difference will remain the same.

Thus;

Potential Difference = 14 V

6 0

3 years ago

The sun is more massive than the moon, but the sun is farther from the earth. Which one exerts a greater gravitational force on

love history [14]

Answer:

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Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

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