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4 years ago

MATHPHYS PLEASE HELP

Physics

2 answers:

solmaris [256]4 years ago

3 0

Explanation:

Momentum is mass times speed.

p = mv

a) p = (1500 kg) (25.0 m/s) = 37,500 kg m/s

b) p = (40,000 kg) (1.00 m/s) = 40,000 kg m/s

The truck has more linear momentum.

Momentum in the y direction:

pᵧ = (1500 kg) (25.0 m/s) = 37,500 kg m/s

Momentum in the x direction:

pₓ = (1500 kg) (15.0 m/s) = 22,500 kg m/s

Total linear momentum:

p² = pₓ² + pᵧ²

p² = (22,500 kg m/s)² + (37,500 kg m/s)²

p = 43,700 kg m/s

nata0808 [166]4 years ago

3 0

Answer:

p = 43,700 kg m/s

Explanation:

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How do i solve for the point of equigravity between two planets, given their mass ratio and the distance between them ?

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<h3>Gravitational force between two planets</h3>

The gravitational force between two planets is calculated as follows;

F = GM₁M₂/R²

where;

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2 years ago

A 3.00 m-long 6.00-kg ladder pivoted at the top hangs down from a platform at the circus. A 42.0-kg trapeze artist climbs to a p

statuscvo [17]

Answer:

The period of the system of ladder and woman, T = 2.5 seconds

Explanation:

Mass of the ladder, $m_1 = 6 kg$

Mass of the artiste, $m_2 = 42.0 kg$

Length of the ladder, L = 42.0 kg

The total moment of inertia can be calculated using the equation:

$I = \frac{1}{3} M_1 L^2 + m_2 (\frac{L}{2} )^2\\I = \frac{1}{3} *6*3^2 + 42* (\frac{3}{2} )^2\\I = 18 + 94.5\\I = 112.5 kg m^2$

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The frequency of the system of ladder and woman follows that of a physical pendulum which can be given by the equation:

$f = \frac{1}{2\pi } \sqrt{\frac{mgD}{I} } \\f = \frac{1}{2\pi } \sqrt{\frac{48*9.8*1.5}{112.5} }\\f = 0.4$

The period of the system of ladder and woman is given by:

T = 1/f

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T = 2.5 seconds

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3 years ago

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