The energy has to be conserved thus the final energy level will always be equal to the initial state .. the initial state has 90j of potential energy and 10j of kinetic energy the total energy is equal to = 100j .
now for the second condition the kinetic energy is 90j and the total energy is 100j thus 100j-90j = 10j of potential energy
Let x be the new volume
10x = 20(5)
10x = 100
x = 10
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Answer:
The answer is "
"
Explanation:
Using the law of conservation for energy. Equating the kinetic energy to the potential energy.
Calculating the closest distance:


Answer:
A) ( - 200t + 40 ) volts
B) b) anticlockwise , c) anticlockwise , d) clockwise , e) clockwise
Explanation:
Given data:
magnetic flux (Φm) = 5.0t^2 − 2.0t
number of turns = 20
<u>a) determine induced emf </u>
E = - N 
= - N ( 10t - 2 ) = - 20 ( 10t - 2 )
= - 200t + 40 volts
<u>b) Determine direction of induced current </u>
i) at t = 0
E = - 0 + 40 ( anticlockwise direction )
ii) at t = 0.10
E = -20 + 40 = 20 ( anticlockwise direction )
iii) at t = 1
E = - 200 + 40 = - 160 ( clockwise direction)
iv) at t = 2
E = -400 + 40 = - 360 ( clockwise direction )