Answer:
When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.
The corresponding relation for diffraction is
,
where 
is the wavelength of light, 
is the slit width, and 
is the diffraction angle.
From this relation we clearly see that the diffraction angle is directly proportional to the wavelength of light—longer the wavelength larger the diffraction angle.
Answer:
1) Hence, the period is 0.33 s.
2) The amplitude is 10 cm.
Explanation:
1) The period is given by:
Where:
f: is the frequency = 3 bob up and down each second = 3 s⁻¹ = 3 Hz
Hence, the period is 0.33 s.
2) The amplitude is the distance between the equilibrium position and the maximum position traveled by the spring. Since the spring is moving up and down over a distance of 20 cm, then the amplitude is:
Therefore, the amplitude is 10 cm.
I hope it helps you!
The answers to all the research related questions are written below.
<h3>What is atom?</h3>
Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.
James Chadwick tracked down the neutron in 1932 and was conceded the Nobel Prize for science in 1935 held in a German prison camp for all of World War 1, he driven the British gathering inside the Manhattan Extend, in which the UK and Canada maintained the USA's World War 2 effort to build the world with nuclear bomb.
Chadwick and Rutherford were the first scientists who measured the nucleus radius using the alpha particles. He did Gold foil experiment to find the size of nucleus.
The contributions are present in the modern atomic model. They are: All matter consists of atoms. Atoms of the same element are the same in size and atoms of different elements are different. Atoms combine in whole-number ratios to form compounds.
Learn more about atoms.
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Answer:
v = 12.12 m/s
Explanation:
It is given that,
Radius of circle, r = 30 m
The coefficient friction between tires and road is 0.5,
The centripetal force is balanced by the force of friction such that,
v = 12.12 m/s
So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.
Answer:
1. True WA > WB > WC
Explanation:
In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.
A) Work is the product of force by distance and the cosine of the angle between them
WA = W h cos 0
WA = mg h
B) On a ramp without rubbing
Sin30 = h / L
L = h / sin 30
WB = F d cos θ
WB = F L cos 30
WB = mf (h / sin30) cos 30
WB = mg h ctan 30
C) Ramp with rubbing
W sin 30 - fr = ma
N- Wcos30 = 0
W sin 30 - μ W cos 30 = ma
F = W (sin30 - μ cos30)
WC = mg (sin30 - μ cos30) h / sin30
Wc = mg (1 - μ ctan30) h
When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum
Let's review the claims
1. True The work of gravity is the greatest and the work where there is friction is the least
2 False. The job where there is friction is the least
3 False work with rubbing is the least
4 False work with rubbing is the least
