All three windows are the same size.
A has 10 complete waves visible through the window. B has 3, and C has 4.
So A must have the smallest wavelengths.
Answer: y = 2.4×10^-6m or y= 2.4μm
Explanation: The formulae for the distance between the central bright fringe to any other fringe in pattern is given as
y = R×mλ/d
Where y = distance between nth fringe and Central bright spot fringe.
m = position of fringe = 4
λ = wavelength of light= 600nm = 600×10^-9 m
d = distance between slits = 1.50×10^-5m
R = distance between slit and screen = 2m
y = 2 × 4 × 600×10^-9/2
y = 4800×10^-9/2
y = 2400 × 10^-9
y = 2.4×10^-6m or y= 2.4μm
Answer:
(b) The electrons, because they have the smaller momentum and, hence, the larger de Broglie wavelength
Explanation:
de Broglie wavelength λ = h / m v
Since both electrons and protons have same velocity , momentum mv will be less for electrons because mass of electron is less .
for electron , momentum is less so . Therefore de Broglie wavelength λ will be more for electrons .
Amount of diffraction that is angle of diffraction is proportional to λ
Therefore electrons having greater de Broglie wavelength will show greater diffraction.
Given:
Sample 1:
Chloroform is 
12 g Carbon
1.01 g Hydrogen
106.4 g Cl
Sample 2:
30.0 g of Carbon
Solution:
mass of chloroform from sample 1:
12 + 1.01 +106.4 =119.41 g
Now, for the total mass of chloroform in sample 2:
mass of chloroform 
mass of chloroform = 119.41 
= 298.53 g
