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3 years ago

what is the acceleration of a 2,000- kilogram truck if a force of 4,200. N is used to make it start moving forward?

1 answer:

5 0

Newton's 2nd law of motion: Force = (mass) x (acceleration)

Divide each side by (mass) : Acceleration = (force) / (mass)

Acceleration of the truck = (4,200 N) / (2,000 kg) = 2.1 m/s²

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3 years ago

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Annette [7]

Answer: -194 mph

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3 years ago

A truck is traveling east at 80 km/h. At an intersection 32 km ahead, a car is traveling north at 50 km/h. How long after this m

nirvana33 [79]

The time elapsed when the vehicles are closest to each other is 20 min.

The given parameters:

Speed of the truck, u = 80 km/h
Distance, d = 32 km
Speed of the car, v = 50 km/h

<h3>Principles of relative speed</h3>

The time elapsed when the cars are close to each other is calculated by applying the principles of relative speed.

$(V_r) t = d\\\\V_r^2 = 50^2 + 80^2\\\\V_r =\sqrt{50^2 + 80^2} \\\\V_r = 94.34 \ km/h$

$94.34 t = 32\\\\t = \frac{32}{94.34} \\\\t = 0.34 \ hr\\\\t \approx 20 \min$

Thus, the time elapsed when the vehicles are closest to each other is 20 min.

Learn more about relative velocity here: brainly.com/question/24430414

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