A force of 6 N acts on a 33 kg object for 9 seconds. What is the objects change in velocity?
1 answer:
You might be interested in
Answer:
6.88 mA
Explanation:
Given:
Resistance, R = 594 Ω
Capacitance = 1.3 μF
emf, V = 6.53 V
Time, t = 1 time constant
Now,
The initial current, I₀ =
or
I₀ =
or
I₀ = 0.0109 A
also,
I =
here,
τ = time constant
e = 2.717
on substituting the respective values, we get
I =
or
I =
or
I = 0.00688 A
or
I = 6.88 mA
The force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:
- v(x) =6 N
- v(y) = 10.39 N
To solve this exercise the formulas and procedures we will use are:
- v(x) = v * cosine (angle)
- v(y) = v * sine (angle).
Where:
- v= magnitude of the vector
- v(x) = component of the vector on the (x) axis
- v(y) = component of the vector on the (y) axis
- angle = angle
Information about the problem:
- angle = 60º
- v = 12.0 N
- v(x)= ?
- v(y)= ?
Applying the formula of the component of the vector in the (x) axis we have:
v(x) = v * cosine (angle).
v(x) = 12.0 N * cosine (60º)
v(x) =6 N
Applying the formula of the component of the vector in the (y) axis we have:
v(y) = v * sine (angle)
v(y) = 12.0 N * sine (60º)
v(y) = 10.39 N
<h3>What is a vector?</h3>It can be said to be a straight line described by a point (a) and (b) that has direction and sense.
Learn more about vector at: brainly.com/question/2094736
#SPJ4
