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A straight, vertical wire carries a current of 2.15 A downward in a region between the poles of a large superconducting electrom

enot [183]

Answer:

a) F = 0.01234N to the south direction

b) F = 0.01234N to the north direction

c) F = 0.01234N

d) North of West

Explanation:

The magnetic force in a magnetic field is given by:

$F = BIlsin \theta$

Length of the wire, l = 1 cm = 0.01 m

Current flowing through the wire, I = 2.15 A

a) If the magnetic field direction is east

∅ = 90

F = 0.574 * 2.15 * 0.01

F = 0.01234 N to the south direction according to the Fleming's Right Hand Rule

b) If the magnetic field direction is south

The magnitude of the magnetic force remains the same

That is , F = BIL sin 90

F = 0.01234 N to the west

c) If the magnetic field direction is 30 degrees south

The angle between the magnetic field and the length of the wire still remains 90 degrees

Therefore the magnitude of the force still remains 0.01234

F = 0.01234 N

d) the direction of the force is the North of West

8 0

3 years ago

If you stretch a rubber hose and pluck it, you can observe a pulse traveling up and down the hose.(i) What happens to the speed

Monica [59]

The thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

<h3>What is wage speed?</h3>

It should be noted that wave speed simply means the distance that a wave travels during a particular time.

It should be noted that higher tension leads to an increase in the speed of the wave.

Therefore, the thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

Learn more about speed on:

brainly.com/question/13943409

#SPJ4

4 0

2 years ago

To test the quality of a tennis ball, you drop it onto the floor from a height of 4.00 m. It rebounds to a height of 2.00 m. If

arlik [135]

Answer:

Part a)

$a = 1260.3 m/s^2$

Part b)

Direction = upwards

Explanation:

When ball is dropped from height h = 4.0 m

then the speed of the ball just before it will strike the ground is given as

$v_f^2 - v_i^2 = 2 a d$

$v_1^2 - 0^2 = 2(9.81)(4.0)$

$v_1 = 8.86 m/s$

Now ball will rebound to height h = 2.00 m

so the velocity of ball just after it will rebound is given as

$v_f^2 - v_i^2 = 2 a d$

$0 - v_2^2 = 2(-9.81)(2.00)$

$v_2 = 6.26 m/s$

Part a)

Average acceleration is given as

$a = \frac{v_f - v_i}{\Delta t}$

$a = \frac{6.26 - (-8.86)}{12.0 \times 10^{-3}}$

$a = 1260.35 m/s^2$

Part B)

As we know that ball rebounds upwards after collision while before collision it is moving downwards

So the direction of the acceleration is vertically upwards

7 0

3 years ago

A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slit

JulsSmile [24]

I am assuming you know the relation obtained between slit width, distance of screen from slits, distance of interference pattern obtained on the screen from the center and the wavelength of monochromatic light used in Young's Double Slit experiment.
λ = $\frac{y*d}{D} = \frac{3.55*10^{-3}*1.25*10^{-4} }{2.25} = 1.97*10^{-7} m$
λ ~ 1.97 ×10⁻⁷m

7 0

3 years ago

A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and

victus00 [196]

Answer:

a) $t=195.948N.m$