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Sophie [7]
3 years ago
7

Given the following sets of values, calculate the unknown

Chemistry
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

3.91 L

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information given in this question,

P = 5.23 atm

V= ?

n = 0.831 mol

T = 27°C = 27 + 273 = 300K

Using PV = nRT

V = nRT/P

V = (0.831 × 0.0821 × 300) ÷ 5.23

V = 20.47 ÷ 5.23

V = 3.91 L

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What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL
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Density is weight by volume.   

First.  If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL

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In a closed container, the vapor pressure of 10 mL of ethanol at 20 degrees C is 5.85 kPa. What is the vapor pressure of 20 mL o
natulia [17]

Answer:

{P_2}=2.925\ kPa

Explanation:

At same temperature and same number of moles, Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

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Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

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