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Rom4ik [11]
3 years ago
10

Which option is an element A: carbon dioxide B: Water C: Air D: Carbon

Chemistry
2 answers:
7nadin3 [17]3 years ago
5 0

Answer:

carbon is an element (D)

Explanation:

An element is a substance composed of a single type of atom. In this case, only carbon is an element.

Ivenika [448]3 years ago
3 0

Answer:

D: Carbon

Explanation:

The periodic table lists all the known elements. When looking at it, the only choice you will find is carbon. Therefore, carbon is the element.

Carbon is also by itself, just C.

Water is H2O, which is a molecule due to the 2 different elements.

Carbon Dioxide is CO2, which is a molecule due to the 2 different elements.

Air is just a mixture of different gas molecules, so therefore it is not an element.  

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The mass of the ice cubes and the water will be equal because the same amount of matter is in the beaker.

Matter is anything that has mass and occupy space. All substances are composed of matter. According to the law of conservation of mass, matter can neither be created nor destroyed but can be converted from one form to another.

Since mass is the quantity of matter in a substance, the mass of the ice cubes and the water will be equal because the same amount of matter is in the beaker.

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3 years ago
1 Balance each equation. Paragraph Styles Voice Sensity 2) Indicate the type of reaction by classifying each reaction as single
nika2105 [10]

1. Double replacement (DR)

2. Decomposition (D)

<h3>Further explanation</h3>

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General form :

AB + CD -> AD + CB

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General form :

AB ---> A + B

6 0
3 years ago
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Rufina [12.5K]

Answer:

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2 years ago
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Assuming that all the energy given off in the reaction goes to heating up only the air in the house, determine the mass of metha
nirvana33 [79]

Answer:

0.92 kg

Explanation:

The volume occupied by the air is:

35.0m\times 35.0m \times 3.2m \times \frac{10^{3}L }{1m^{3} } =3.9 \times 10^{6} L

The moles of air are:

3.9 \times 10^{6} L \times \frac{1.00mol}{22.4L} =1.7 \times 10^{5}mol

The heat required to heat the air by 10.0 °C (or 10.0 K) is:

1.7 \times 10^{5}mol \times \frac{30J}{K.mol} \times 10.0 K = 5.1 \times 10^{7}J

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5.1 \times 10^{7}J \times \frac{1kgCH_{4}}{55.5 \times 10^{6} J } =0.92kgCH_{4}

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3 years ago
What rock forms from magma oozing onto the surface?
timurjin [86]
Answer: A. Igneous rock
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