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Rom4ik [11]
3 years ago
10

Which option is an element A: carbon dioxide B: Water C: Air D: Carbon

Chemistry
2 answers:
7nadin3 [17]3 years ago
5 0

Answer:

carbon is an element (D)

Explanation:

An element is a substance composed of a single type of atom. In this case, only carbon is an element.

Ivenika [448]3 years ago
3 0

Answer:

D: Carbon

Explanation:

The periodic table lists all the known elements. When looking at it, the only choice you will find is carbon. Therefore, carbon is the element.

Carbon is also by itself, just C.

Water is H2O, which is a molecule due to the 2 different elements.

Carbon Dioxide is CO2, which is a molecule due to the 2 different elements.

Air is just a mixture of different gas molecules, so therefore it is not an element.  

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Explanation:

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8 0
2 years ago
Should Scientist be allowed to conduct stem cell research?
Citrus2011 [14]

Answer: Studying stem cells can help scientists understand more about how the body works and how disease develops and affects the body so yes

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7 0
3 years ago
How many grams of Na2O are produced when 70.7 g of Na reacts?<br> 4Na(s)+O2(g)→2Na2O(s)
LUCKY_DIMON [66]

Answer:

95.3 grams.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Na: 22.990;
  • O: 15.999.

How many moles of Na are consumed?

M(\mathrm{Na}) = \rm 22.990\; g\cdot mol^{-1}.

\displaystyle n(\mathrm{Na}) = \frac{m(\mathrm{Na})}{M(\mathrm{Na})} = \rm \frac{70.7\; g}{22.990\;g\cdot mol^{-1}}=3.07525\;mol.

How many moles of \mathrm{Na_2 O} formula units will be produced?

Consider the ratio between the coefficient of \mathrm{Na_2 O} and that of \mathrm{Na} in the equation:

\displaystyle \frac{n(\mathrm{Na_2 O})}{n(\mathrm{Na})} = \frac{2}{4} = \frac{1}{2}.

As a result,

\displaystyle n(\mathrm{Na_2 O}) = n(\mathrm{Na}) \cdot \frac{n(\mathrm{Na_2 O})}{n(\mathrm{Na})} = \rm \frac{1}{2}\times 3.07525\;mol = 1.53763\; mol.

What will be the mass of that many \mathrm{Na_2 O}?

Formula mass of \mathrm{Na_2 O}:

M(\mathrm{Na_2 O}) = \rm 2\times 22.990 + 15.999 = 61.979\; g\cdot mol^{-1}.

m(\mathrm{Na_2 O}) = n(\mathrm{Na_2 O})\cdot M(\mathrm{Na_2 O}) = \rm 1.53763\; mol\times 61.979\; g\cdot mol^{-1} \approx 95.3\; g.

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Substances 1 and 3 both have 2 carbon atoms
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