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igor_vitrenko [27]
3 years ago
15

A solid rubber ball with a mass of 5.9 grams sank in water. A hollow rubber ball with the same mass floats in water. Explain why

this might be. Please answer ASAP!
Chemistry
1 answer:
Stells [14]3 years ago
4 0

Answer:

The hollow ball is more buoyant than the solid ball.

Explanation:

The hollow ball will float while the solid ball sinks because the volume of water displaced by the hollow ball is more than that displaced by the solid ball.

An object floats when it displaces a volume of water equal to its weight.  A solid ball is more compact, and hence, does not displace a lot of water when dropped into a bowl full of water. On the other hand, the hollow ball will have a larger curved surface area, since it has no fill. This will make it displace a larger volume of water and hence make it float.

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plz answer fast Which is not a crystalline allotrope of carbon? Select one: a. soot b. diamond c. graphite
Norma-Jean [14]

Answer:

graphite

Explanation:

Graphite is opaque, a very good lubricant, a good conductor of electricity, and a thermal insulator. Allotropes of carbon are not limited to diamond and graphite, but also include buckyballs (fullerenes), amorphous carbon, glassy carbon, carbon nanofoam, nanotubes, and others.

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

8 0
3 years ago
A biotic factor in a desert ecosystem would be the
valkas [14]
C is correct.

Please vote my answer brainliest. thanks!
6 0
4 years ago
Read 2 more answers
How many liters of water would you need to add to 4.36 moles of NaCl to create a 9.4 M solution?
marishachu [46]

Answer:

0.464 L

Explanation:

Molarity (M) = number moles (n) ÷ volume (V)

According to the information given in this question:

number of moles (n) = 4.36 moles

Molarity = 9.4M

Volume = ?

Using M = n/V

9.4 = 4.36/V

9.4V = 4.36

V = 4.36/9.4

V = 0.464 L

Hence, 0.464L of water are needed the volume of water.

3 0
3 years ago
97
alex41 [277]
B

Please help

Sorry I need 20 characters to submit this Answer that’s why I’m adding more words
5 0
3 years ago
In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?
Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In H_2O , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in Cl^- is -1. On product side, the oxidation number of hydrogen in H_2 is zero and in OH^- the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in Cl_2 is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

8 0
3 years ago
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