Answer:
See below
Step-by-step explanation:
heat gained by metal + heat lost by water = 0
m₁C₁ΔT₁ + m₂C₂ΔT₂ = 0
C₁ = -(m₂C₂ΔT₂)/(m₁ΔT₁)
The factors determining C₁ are
- mass of water
- temperature change of water (T_f - Ti)
- mass of metal
- temperature change of metal (T_f - Ti)
Any factor that makes the numerator higher or the denominator lower than what you thought, will give a calculated C₁ that is too high (and vice versa).
The major sources of uncertainty are probably in determining the temperatures, especially the initial and final temperatures of the metal. However, you will have to decide what the principal factors were in your experiment.
For example, did the metal have a chance to cool during the transfer to the calorimeter? How easy was it to determine the equilibrium temperature, etc?
Factors Affecting the Calculation of Specific Heat Capacity
<u> Too Low </u> <u> Too high </u>
Water Water
Mass less than thought Mass more than thought
Ti lower Ti higher
T_f higher T_f lower
Metal Metal
Mass more than thought Mass less than thought
Ti higher Ti lower
Answer:
Carbon and oxygen are chemically bonded in it.
Explanation:
The other answer choices do not apply for compounds, but rather for mixtures instead.
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Answer:
First confirm the reaction is balanced:
C3H8 + 5O2 --> 3CO2 + 4H20 (3 cabon - check; 8 hydrogen - check; 10 oxygen - check).
a) In the equation there is a 5:1 ratio between propane and oxygen. We also know that number of mole is proportional to pressure and volume. Since pressure is constant (STP) then the volume of O2 is 7.2 * 5 = 36 litres.
b) For a near ideal gas that PV = nRT (combined gas law). So for 7.2 litres propane we find n(propane) = 101.3 * 7.2/8.314*298 ~ 0.29 mole (using metric units throughout for simplicity).
There is a 1:3 ratio between propane and CO2. Therefore 3 * 0.29 = 0.87 mole of CO2 is produced.
MW(CO2) ~ 44 g/mol. Therefore m(CO2) = 44 * 0.87 ~ 38.3 g
c) We know we need more oxygen than propane (due to the 1:5 ratio) so oxygen is the limiting reagent. Again Volume is proportional to number of mole and we see there is a 5:4 ratio between oxygen and water. Therefore the volume of water vapour produced will be (4/5) * 15 = 12 litres.
The other questions use the same technique and will give you some much needed practice.
Explanation:
Barium Chloride
Aluminum Iodide
Lithium Phosphide
Sodium Nitride
Potassium Sulfide
Aluminum Oxide
Sodium Oxide
Rubidium Bromide
Calcium Phosphide
hope this helps for the names
Answer:
8x8 Inc. is a provider of Voice over IP products. 8x8 products include cloud-based voice, contact center, video, mobile and unified communications for businesses.
Explanation:
