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3 years ago

Which type of radioactive decay does not cause change in the atomic mass of the product

Chemistry

1 answer:

Lady bird [3.3K]3 years ago

4 0

Answer:

Gamma decay/radiation

Explanation:

Gamma radiation has no mass and no electrical charge which means no change in the atomic number or mass number when gamma rays are emitted.

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Example 4. Balance the equation below in which methane reacts with oxygen in the atmosphere to release heat and the atoms recomb

Tems11 [23]

Answer:

CH4 + 2O2 ----> CO2 + 2H2O

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3 years ago

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harina [27]

Answer:

a or b

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3 years ago

1. Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O

vovikov84 [41]

1) Balanced equation

C3H8 + 5O2 -> 3 CO2 + 4 H2O

2) 0.700 L C3H8

Given the pressure and temperature do not change, the molar ratio is equivalent to volume ratio

1molC3H8 / 5 mol O2 => 1 L C3H8 / 5 L O2

0.700 L C3H8 / x L O2 = 1 L C3H8 / 5 L O2 => x = 0.700 L C3H8 * 5 L O2 / 1 L C3H8

x = 3.500 L O2

3) CO2 produced

1 L C3H8 / 3 L CO2 = 0.700 L C3H8 / x L CO2 =>

x = 0.700 L C3H8 * 3 L CO2 / 1 L C3H8 = 2.100 L CO2

4) Water vapor produced

1) 1 L C3H8 / 4 L H2O = 0.700 LC3H8 / x L H2O =>

x = 0.700 L C3H8 * 4 L H20 / 1 L C3H8 = 2.800 L H2O

3 0

4 years ago

a gas has a volume of 350 cubic centimeters at 740 mmHg. how many cubic centimeters will the gas occupy at a pressure of 900 mmH

Harrizon [31]

Answer: 287.8 cm3

Explanation:

Given that:

Initial volume of gas V1 = 350 cm3

Initial pressure of gas P1 = 740 mmHg

New volume V2 = ?

New pressure P2 = 900 mmHg

Since, pressure and volume are involved while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

740 mmHg x 350 cm3 = 900mmHg x V2

V2 = (740 mmHg x 350 cm3) /900mmHg

V2 = 259000 mmHg cm3 / 900mmHg

V2 = 287.8 cm3

Thus, the gas will occupy 287.8 cubic centimeters at the new pressure.

3 0

3 years ago

ZnS (s) + AIP(s) → AI₂S₂(s) + Zn P₂(s)

Allisa [31]

Answer:

3 ZnS (s) + 2 AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

Explanation:

I believe you are asking for this reaction to be balanced. However, after looking more closely, those are not the products that would be created from the reactants. Assuming this is a double-displacement reaction, and taking the most common charges of the ions into consideration, the actual products would be AI₂S₃(s) + Zn₃P₂(s). I apologize if I assumed incorrectly.

For an equation to be balanced, there needs to be the same amount of each element on both sides of the equation.

The unbalanced equation:

ZnS (s) + AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

Reactants: 1 zinc, 1 sulfur, 1 aluminum, 1 phosphorus

Products: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

As you can see, there is an unequal amount of each element on the reactants and products side. To balance the equation, coefficients in front of the compound(s) will be necessary.

The balanced equation:

3 ZnS (s) + 2 AIP(s) ---> AI₂S₃(s) + Zn₃P₂(s)

Reactants: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

Products: 3 zinc, 3 sulfur, 2 aluminum, 2 phosphorus

3 0

2 years ago