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3 years ago

Answer these questions plz

Physics

1 answer:

lozanna [386]3 years ago

8 0

1. The property of a conductor by virtue of which it posses the flow of electric current through it is called resistance.

2. The resistance of a conductor depends on the cross sectional area of the conductor and it's resistivity.

3.This id due to the fact that the resistance of a wire is inversely proportional to the square of its diameter.

4.Due to at high temperatures , the alloy donot oxidize. Alloy doesn't melt readily and get deformed.

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A 465 g block slides along a frictionless surface at a speed of 0.35 m/s. It runs into a horizontal massless spring with spring

katovenus [111]

Answer:

a) The duration, during which the block remain in contact with the spring is 0.29 s

b) The period of the simple harmonic oscillatory motion depends only on the mass and spring constant, therefore when the speed is doubled, the duration of contact remains the same as 0.29 s.

Explanation:

Mass of the block = 465 g

Surface speed = 0.35 m/s

Spring constant , k = 54 N/m

$T = 2\times \pi \times \sqrt{\frac{m}{K} } = 2\times \pi \times \sqrt{\frac{0.465}{54} }$ = 0.58 s

a) Since the period for the oscillatory motion is 0.58 s, then the time when the block and spring remain in contact is T/2 = 0.29 s

b) When the speed is doubled, we have

$T = 2\times \pi \times \sqrt{\frac{m}{K} }$

Therefore, since T is only dependent on the mass, m and the spring constant, K, then the time it takes when the speed is doubled remain as

T /2 = 0.29 s

7 0

3 years ago

A rod 14.0 cm long is uniformly charged and has a total charge of 222.0 mc. determine (a) the magnitude and (b) the direction of

Yuri [45]

Electric field due to a charged rod along its axis is given by

$E = \frac{kQ}{(L+r)(r)}$

here we know that

L = 14 cm

r = distance from end of rod

r = 36 - 7 = 29 cm

Q = 222 mC

now we will have

$E = \frac{(9 \times 10^9)(222 \times 10^{-3})}{(0.29)(0.43)}$

$E = 1.6 \times 10^{10} N/C$

6 0

3 years ago

The illuminance due to a 60.0-w lightbulb at 3.0m is 9.35 lx. What is the total luminous flux of the bulb

Furkat [3]

The equation for luminous flux is given as P = 4 $\pi$ $r^{2}$ E
where P is the luminous flux, r is the distance and E is the illumination. The unit for P is lumen, E is lux and r is in meters. Substituting the given to the equation:

P = 4 $\pi$ $r^{2}$ E

P= 4 $\pi$ $(3)^{2}$ (9.35) = 1057.46 lumens (lm)

The total luminous flux is equal to 1057.46 lumens (lm).

3 0

3 years ago

its a hot day at the beach you look at your portable themometer which says its 30°C. what is the temperature in Fahrenheit and K

Nitella [24]

The answer is 86 degrees Fahrenheit.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

A piano has a mass of 185 kg, and the coefficient of friction between it and the floor is 0.39. What is the maximum force of fri

Dimas [21]

Coefficient of friction x mass x g