The answer is A ..........
Resultant force is basically the force left after everything is added.
if a ball is being pushed one one side with 180N, and being pushed on teh opposite side with 84N (I added friction and air resistance since they're acting on the same side), then the resultant force would be:
180N - 84N =<u> 96N</u> (you can determine whether it's positive or negative based on the direction of the vector)
Answer:
d) 1.2 mT
Explanation:
Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.
First of all, we observe that:
- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is
I = 15 A
- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).
Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by
![B=\frac{\mu_0 I}{2\pi r}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_0%20I%7D%7B2%5Cpi%20r%7D)
where
is the vacuum permeability
I = 15 A is the current in the conductor
r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field
Substituting, we find:
![B=\frac{(4\pi\cdot 10^{-7})(15)}{2\pi(0.0025)}=1.2\cdot 10^{-3}T = 1.2 mT](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%284%5Cpi%5Ccdot%2010%5E%7B-7%7D%29%2815%29%7D%7B2%5Cpi%280.0025%29%7D%3D1.2%5Ccdot%2010%5E%7B-3%7DT%20%3D%201.2%20mT)
Answer:
Blue light has the shortest wavelength amongst all the colours that combine to make white light. This means the blue light diffracts (bends) the most out of all of them. There will be no dispersion of colours because ideally, the blue light must consist of only one frequency.