Answer:
-0.73 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum.
In fact, in absence of external forces (the ice is frictionless, so no friction), the total momentum of Aisha + two boots is conserved.
At the beginning, their total momentum is zero, since they are at rest:
(1)
After, their total momentum is:
(2)
where:
M is Aisha's mass
v is Aisha's velocity relative to the ground
m = 4.50 kg is the mass of each boot
v' is the boot's velocity relative to the ground
We can find:
is Aisha's mass (where W = 637 N was her weight)
v' can be rewritten as:
![v'=v+6](https://tex.z-dn.net/?f=v%27%3Dv%2B6)
because 6 m/s is the velocity of the boots relative to her, while v' is their velocity relative to the ground.
Substituting and combining (1) and (2) we find:
![0=Mv+2m(v+6)\\0=Mv+2mv+12m\\v=\frac{-12m}{M+2m}=\frac{-12(4.50)}{65+2(4.50)}=-0.73 m/s](https://tex.z-dn.net/?f=0%3DMv%2B2m%28v%2B6%29%5C%5C0%3DMv%2B2mv%2B12m%5C%5Cv%3D%5Cfrac%7B-12m%7D%7BM%2B2m%7D%3D%5Cfrac%7B-12%284.50%29%7D%7B65%2B2%284.50%29%7D%3D-0.73%20m%2Fs)
and the negative sign indicates that the direction is opposite to that of the boots.
Answer:
γ = 0.06563 N / m
9.78% difference
Explanation:
Solution:-
- Surface tension is the ability of any fluid to resist any external force which causes a decreases in surface area of the impact area due to inward compressive forces. These compressive forces occur due to cohesive nature of the fluid molecules.
- Mathematically, surface tension ( γ ) is defined as the force felt per unit length by the fluid.
γ = F / L
Where,
F: Force imparted
L: The length over which force is felt
- We are given the mass ( M ) of ( n = 100 ) water droplets to e 3.78 g. The mass of a single droplet ( m ) can be evaluated as follows:
m = M / n
m = 3.78 / 100
m = 0.0378 g
- The force ( F ) imparted by a single drop of water from the burette can be determined from the force balance on a single droplet. Assuming the distance over which the drop falls is negligible and resistive forces are negligible. Then the only force acting on the droplet is due to gravity:
F = m*g
F = 0.0378*9.81*10^-3
F = 0.000370818 N
- The length over which the force is felt can be magnified into a circular area with diameter equal to that of a single droplet ( d ). The circumferential length ( L ) of the droplet would be as follows:
L = π*d
L = π*( 0.0018 )
L = 0.00565 m
- Then the surface tension would be:
γ = F / L
γ = 0.000370818 / 0.00565
γ = 0.06563 N / m
- The tabulated value of water's surface tension is given as follows:
γa = 0.07275 N/m
- We will determine the percentage difference between the value evaluated and tabulated value as follows:
![p.diff = \frac{gamma_a - gamma}{gamma_a} * 100\\\\p.diff = \frac{0.07275- 0.06563}{0.07275} * 100 \\\\p.diff = 9.78 %](https://tex.z-dn.net/?f=p.diff%20%3D%20%5Cfrac%7Bgamma_a%20-%20gamma%7D%7Bgamma_a%7D%20%2A%20100%5C%5C%5C%5Cp.diff%20%3D%20%5Cfrac%7B0.07275-%200.06563%7D%7B0.07275%7D%20%2A%20100%20%5C%5C%5C%5Cp.diff%20%3D%209.78%20%25)
- The %difference between is within the allowable practical limits of 10%. Hence, the evaluated value ( γ = 0.06563 N / m ) can be accepted with 9.78% error.
Answer:
Hi myself Shrushtee
Explanation:
Neutral carbon-12 (or any carbon atom) has 6 electrons with a total negative charge of 6e- orbiting a nucleus with a total positive charge of 6e+, so that the total net charge is zero. The nucleus is made up of 6 protons, each with a positive charge of e+, and 6 neutrons, each with zero charge.
please mark me as brainleist
Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.
<h3>What is electrical force?</h3>
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The given data in the problem is
q₁ is the negative charge = 6 µC=6×10⁻⁶ C
q₂ is the positive charge = 3 µC=3×10⁻⁶ C
r is the distance between the charges=0.002 m
is the electric force =?
The value of electric force will be;
![\rm F_E= \frac{Kq_1q_2}{r^2} \\\\ F_E= \frac{9\times 10^9\times 6\times 10^{-6}\times3\times10^{-6}}{(0.002)^2}\\\\ \rm F_E=4.05\times10^4\;N](https://tex.z-dn.net/?f=%5Crm%20F_E%3D%20%5Cfrac%7BKq_1q_2%7D%7Br%5E2%7D%20%5C%5C%5C%5C%20F_E%3D%20%5Cfrac%7B9%5Ctimes%2010%5E9%5Ctimes%206%5Ctimes%2010%5E%7B-6%7D%5Ctimes3%5Ctimes10%5E%7B-6%7D%7D%7B%280.002%29%5E2%7D%5C%5C%5C%5C%20%5Crm%20F_E%3D4.05%5Ctimes10%5E4%5C%3BN)
Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.
To learn more about the electrical force refer to the link;
brainly.com/question/1076352