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Alchen [17]
3 years ago
11

Two ropes are attached to a 40-kg object. The first rope applies a force of 50 N and the second, 40 N. If the two ropes are perp

endicular to each other, what is the resultant magnitude of the acceleration of the object?
Physics
1 answer:
Montano1993 [528]3 years ago
4 0

To solve this problem we will use the concepts related to the resulting Vector Force product of two components, that is,

|\vec{F}| = \sqrt{F_x^2+F_y^2}

If we take the Force of 50 N as the force in the X direction and the Force of 40 N in the Y direction we will have to:

|\vec{F}| = \sqrt{F_x^2+F_y^2}

|\vec{F}| = \sqrt{(50)^2+(40)^2}

|\vec{F}| = 64.03N

Finally, since Newton's second law, acceleration can be determined as

F = ma

a = \frac{F}{m}

a = \frac{ 64.03}{40}

a = 1.6m/s^2

Therefore the resultant magnitude of the acceleration of the object is 1.6m/s^2

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