Answer:
Magnitude of the force on proton = F = 1.1085 × 10^-15 N
Explanation:
Charge on proton = q = 1.60 × 10^-19 C
Velocity of proton = V = 4.0 × 10^4 m/s
Magnetic field = B = 0.20 T
Angle between V and B = θ = 60
We know that,
F = qVBsin θ = (1.60 × 10^-19)( 4.0 × 10^4)( 0.20)sin(60)
F = 1.1085 × 10^-15 N
In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s
Answer:
Explanation:
m1 = 24 kg
m2 = 63 kg
(a) Let the tension is T1 in upper rope and T2 in lower rope.
Use Newtons' second law on m2.
T2 = 856.8 N
Apply Newton's second law on m1
T1 = 1183.2 N
(b)
Use Newtons' second law on m2.
T2 = 378 N
Apply Newton's second law on m1
T1 = 522 N