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3 years ago

Cecelia dropped a ball from a height of 2 m. The ball fell in a straight path down to the ground.

Physics

2 answers:

ohaa [14]3 years ago

6 0

I’m pretty sure it is dropping it horizontally at a slower speed. Sorry if I’m wrong.

lora16 [44]3 years ago

3 0

Agreed it only makes since

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What is the wavelength, in nm, of the line in the hydrogen spectrum when one n value is 3 and the other n value is 6?

iren [92.7K]

Answer:

$\lambda=1090nm$

Explanation:

Rydberg formula is used to calculate the wavelengths of the spectral lines of many chemical elements. For the hydrogen, is defined as:

$\frac{1}{\lambda}=R_H(\frac{1}{n_1^2}-\frac{1}{n_2^2})$

Where $R_H$ is the Rydberg constant for hydrogen and $n_1$ , $n_2$ are the lower energy state and the higher energy state, respectively.

$\frac{1}{\lambda}=1.10*10^{7}m^{-1}(\frac{1}{3^2}-\frac{1}{6^2})\\\frac{1}{\lambda}=9.17*10^{5}m^{-1}\\\lambda=\frac{1}{1.09*10^{6}m^{-1}}\\\lambda=1.09*10^{-6}m*\frac{10^{9}nm}{1m}\\\lambda=1090nm$

4 0

3 years ago

Group of physics students are asked to demonstrate Ohm’s Law in parallel circuits. Using their knowledge of Ohm’s Law and the r

astra-53 [7]

The student’s suggestion who provides enough evidence to be able to determine the value of each resistor is student D.

<h3>What is current?</h3>

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

For the given set of parallel resistors, we need to find the resistance of each resistor.

From the Ohm's law, V =IR

R = V/I

Resistance value depends upon the voltage difference across the resistor and the current flowing through that resistance.

Thus, the student D gives enough evidence to find resistance of the circuit is

Learn more about current.

brainly.com/question/10677063

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8 0

1 year ago

A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i

sammy [17]

Answer:

$-0.25 rad/s^2$

Explanation:

The equivalent of Newton's second law for rotational motions is:

$\tau = I \alpha$

where

$\tau$ is the net torque applied to the object

I is the moment of inertia

$\alpha$ is the angular acceleration

In this problem we have:

$\tau = -12.5 Nm$ (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

$I=50.0 kg m^2$ is the moment of inertia

Solving for $\alpha$ , we find the angular acceleration:

$\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2$

3 0

3 years ago

A motorcycle traveling at 25 m/s accelerates ya a rate of 7.0 m/s2 for 6.0 seconds. What is the final velocity of the motorcycle

frutty [35]

First write down all your known variables:

vi = 25m/s

a = 7.0m/s^2

t = 6.0s

vf = ?

Then choose the kinematic equation that relates all the variables and solve for the unknown variable:

vf = vi + at

vf = (25) + (7.0)(6.0)

vf = 67m/s

The final velocity of the motorcycle is 67m/s.

4 0

3 years ago

The period of an oscillating particle is 32 s, and its amplitude is 15 cm. at t = 0, it is at its equilibrium position. find the

morpeh [17]

At t=0, the particle was at its equilibrium position. The time period is 32 seconds, so in 8 seconds, it will reach the extreme location once, and hence, in 8 seconds, it will cover a distance equivalent to its amplitude.

5 0

3 years ago