The possible magnitude for the force of static friction on the stationary cart is 72.1 N.
The given parameters:
- <em>Applied force on the cart, F = 72.1 N</em>
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Based on Newton's second law of motion, the force applied to object is directly proportional to the product of mass and acceleration of the object.
F = ma
Static frictional force is the force resisting the motion of an object at rest.

where;
is the frictional force

Thus, the possible magnitude for the force of static friction on the stationary cart is 72.1 N.
Learn more about Newton's second law of motion: brainly.com/question/25307325
Divide CFU of Dilution. Divide the CFU of the dilution (the number of colonies you counted) by the result from step 4. For this example, you work out 46 ÷ 1/1000, which is the same as 46 x 1,000. The result is 46,000 CFU in the original sample.
Answer:
d. According to the previous theorem:
(kh^2)/2-mgh-(m(2v)^2)/2=0,
126h^2-2.577h-8.236=0,
h=0.266 m.
Explanation:
B, Studying how ones' character changes over time... That's the only one that has to deal with personality.
It would be option A (a decrease in mass with an increase in volume)