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Arte-miy333 [17]
4 years ago
9

I have a pure breed homozygous long claw monster (CC), Claude and

Physics
1 answer:
Colt1911 [192]4 years ago
8 0
Idkndkfkfkfrkkffkg. Kdirkrif nejrnrbd idleness r t t y y t r y y y r r d f y y t td
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The________is a measure of the number of waves that pass a point in a given amount of time
cricket20 [7]
Frequency measures how many waves pass a certain point in a given amount of time.
High frequency means the waves are closer together and more frequent, making for a lower wave length.
Low frequency means the waves are farther apart and less frequent, making for a higher wave length.

So the answer is frequency.
4 0
4 years ago
Read 2 more answers
Can someone help me with this Physics question please?
strojnjashka [21]

Answer:

Explanation:

The formula for this, the easy one, is

N=N_0(\frac{1}{2})^{\frac{t}{H} where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:

N=48.0(\frac{1}{2})^{\frac{49.2}{12.3} and simplifying a bit:

N=48.0(.5)^4 and

N = 48.0(.0625) so

N = 3 mg left after 12.3 years

6 0
3 years ago
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a race car accelerates uniformly from 18.5m/s to 46.1m/s in 2.4 seconds. determine the acceleration of the car and the distance
8_murik_8 [283]

The car's (average) acceleration would be

a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}

The car's position over time would be given by

x=v_0t+\dfrac12at^2

so that after 2.4 seconds, the car will have traveled a distance of

x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2

\implies x=77.5\,\mathrm m

7 0
3 years ago
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Which is not a way to accelerate an object?
densk [106]
I would definitely think its B....
3 0
3 years ago
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If a transformer has a primary with 100 V and fifty coils, and a secondary that yields 20 V, how many coils are on the secondary
melomori [17]
Ideally, if all the magnetic of one winding cuts the other winding, and there isn't any loss in the transformer core or the resistance of the wire, then the voltage across each winding is proportional to the number of turns in its coil.

If you apply 100 V to a winding of 50 turns, then a winding that yields 20 volts
must be wound with

(20/100) of 50 turns = 10 turns
7 0
3 years ago
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