What’s the unit for velocity?

il63 [147K]

Explanation:

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Reduction of processed foods, sugars and soft drinks.

Increased fiber intake
Daily walks of at least 30 minutes
Increased water consumption
Increased consumption of fruits and vegetables
Incorporate meditation and yoga practices

6 0

3 years ago

A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g

7nadin3 [17]

Answer:

(a) r = 1.062·R $_E$ = $\frac{531}{500} R_E$

(b) r = $\frac{33}{25} R_E$

(c) Zero

Explanation:

Here we have escape velocity v $_e$ given by

$v_e =\sqrt{\frac{2GM}{R_E} }$ and the maximum height given by

$\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}$

Therefore, when the initial speed is 0.241v $_e$ we have

v = $0.241\times \sqrt{\frac{2GM}{R_E} }$ so that;

v² = $0.058081\times {\frac{2GM}{R_E} }$

v² = ${\frac{0.116162\times GM}{R_E} }$

$\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}$ is then

$\frac{1}{2} {\frac{0.116162\times GM}{R_E} }-\frac{GM}{R_E} = -\frac{GM}{r}$

Which gives

$-\frac{0.941919}{R_E} = -\frac{1}{r}$ or

r = 1.062·R $_E$

(b) Here we have

$K_i = 0.241\times \frac{1}{2} \times m \times v_e^2 = 0.241\times \frac{1}{2} \times m \times \frac{2GM}{R_E} = \frac{0.241mGM}{R_E}$

Therefore we put $\frac{0.241GM}{R_E}$ in the maximum height equation to get

$\frac{0.241}{R_E} -\frac{1}{R_E} =-\frac{1}{r}$

From which we get

r = 1.32·R $_E$

(c) The we have the least initial mechanical energy, ME given by

ME = KE - PE

Where the KE = PE required to leave the earth we have

ME = KE - KE = 0

The least initial mechanical energy to leave the earth is zero.

3 0

3 years ago

Read 2 more answers

W imieniu państwa napisz zaproszenie dla rodzeństwa na uroczystą kolacje

HACTEHA [7]

On behalf of the state, write an invitation for the siblings for the gala dinner

Hello there, we would like to welcome you to the gala dinner hope you can come :)

8 0

3 years ago

Suppose that the current in the solenoid is i(t). The self-inductance L is related to the self-induced EMF E(t) by the equation

Artemon [7]

Answer:

L = μ₀ n r / 2I

Explanation:

This exercise we must relate several equations, let's start writing the voltage in a coil

$E_{L}$ = - L dI / dt

Let's use Faraday's law

E = - d Ф_B / dt

in the case of the coil this voltage is the same, so we can equal the two relationships

- d Ф_B / dt = - L dI / dt

The magnetic flux is the sum of the flux in each turn, if there are n turns in the coil

n d Ф_B = L dI

we can remove the differentials

n Ф_B = L I

magnetic flux is defined by

Ф_B = B . A

in this case the direction of the magnetic field is along the coil and the normal direction to the area as well, therefore the scalar product is reduced to the algebraic product

n B A = L I

the loop area is

A = π R²

we substitute

n B π R² = L I (1)

To find the magnetic field in the coil let's use Ampere's law

∫ B. ds = μ₀ I

where B is the magnetic field and s is the current circulation, in the coil the current circulates along the length of the coil

s = 2π R

we solve

B 2ππ R = μ₀ I

B = μ₀ I / 2πR

we substitute in

n ( μ₀ I / 2πR) π R² = L I

n μ₀ R / 2 = L I

L = μ₀ n r / 2I

4 0

3 years ago

A light wave has a wavelength of 450 nanometers. What is the frequency of this light?

Zolol [24]

Answer:

Frequency, $f=6.67\times 10^{14}\ Hz$

Explanation:

Wavelength of a light wave is 450 nm. It is required to find the frequency of this light wave. The speed of light is given by c. So,

$c=f\lambda$

f is the frequency of this light

$f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{450\times 10^{-9}}\\\\f=6.67\times 10^{14}\ Hz$

So, the frequency of this light is $6.67\times 10^{14}\ Hz$ .

3 0

3 years ago