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tiny-mole [99]
2 years ago
11

When using the lens equation, a negative value as the solution for di indicates that the image is real. Virtual. Upright. Invert

ed.
Physics
1 answer:
Kisachek [45]2 years ago
3 0

Option B is correct. A negative value as the solution indicates that the image is Virtual.

<h3>What is the lens equation?</h3>

The Lens formula describes the relationship between the distance of an image (v), the distance of an object (u), and the focal length (f) of the lens in optics.

The lens equation is given below;

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}

When light beams from the same spot on an item reflect off a mirror and diverge or spread apart, virtual pictures are formed.

Hence option B is correct. A negative value as the solution indicates that the image is Virtual.

To learn more about the lens equation refer to the link;

brainly.com/question/15854388

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A 16.0kg canoe moving to the left at 12.5m/s makes an elastic head-on collision with a 14.0kg raft moving to the right at 16.0m/
kherson [118]

The canoe is moving at 14.1 m/s to the right after the collision.

Explanation:

According to the law of conservation of momentum, in absence of external forces the total momentum of the system must be conserved before and after the collision. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 16.0 kg is the mass of the canoe

u_1 = -12.5 m/s is the initial velocity of canoe (we take right as positive direction, and since the canoe is moving to the left, its velocity is negative)

v_1 is the final velocity of the canoe

m_2 = 14.0 kg is the mass of the raft

u_2 = +16.0 m/s is the initial velocity of the raft

v_2 = -14.4 m/s is the final velocity of the raft

Re-arranging the equation and substituting the values, we find: the final velocity of the canoe:

v_1 = \frac{m_1 u_1 + m_2 u_2-m_2 v_2}{m_1}=\frac{(16.0)(-12.5)+(14.0)(16.0)-(14.0)(-14.4)}{16.0}=+14.1 m/s

So, the canoe is moving at 14.1 m/s to the right after the collision.

Learn more about momentum:

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