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tiny-mole [99]
2 years ago
11

When using the lens equation, a negative value as the solution for di indicates that the image is real. Virtual. Upright. Invert

ed.
Physics
1 answer:
Kisachek [45]2 years ago
3 0

Option B is correct. A negative value as the solution indicates that the image is Virtual.

<h3>What is the lens equation?</h3>

The Lens formula describes the relationship between the distance of an image (v), the distance of an object (u), and the focal length (f) of the lens in optics.

The lens equation is given below;

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}

When light beams from the same spot on an item reflect off a mirror and diverge or spread apart, virtual pictures are formed.

Hence option B is correct. A negative value as the solution indicates that the image is Virtual.

To learn more about the lens equation refer to the link;

brainly.com/question/15854388

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Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10^4 Pa. If
frez [133]

Answer:

p2 = 9.8×10^4 Pa

Explanation:

Total pressure is constant and PT = P = 1/2×ρ×v^2  

So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2

from continuity we have ρ×A1×v1 = ρ×A2×v2  

v2 = v1×A1/A2  

and  

r2 = 2×r1

then:

A2 = 4×A1  

so,

v2 = (v1)/4  

then:

p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2  

p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)  

     = 9.75×10^4 Pa

    = 9.8×10^4 Pa

Therefore, the pressure in the wider section is 9.8×10^4 Pa

5 0
3 years ago
During which of the following chemical changes does C02 bubbles form?
sweet [91]

Answer:

Carbon dioxide is formed when sodium carbonate or sodium hydrogen carbonate is reacted with any mineral acid or organic acid

Explanation:

.

7 0
3 years ago
Biological factor related to antisocial personality disorder is
dusya [7]
Schizotypal personality disorder and borderline personality disorder 
4 0
3 years ago
Read 2 more answers
how long does it take an acorn to hit the ground after dropping from the branch of a tree 50.0m high? remember that g=9.8m/s^2
NeX [460]
D = V1( t ) + 1/2g( t )^2
50m = 0m/s( t ) + 1/2(9.8m/s^2)*( t )^2
V1*t cancels out
50m = (4.9m/s^2)*(t)^2
50m/(4.9m/s^2) = t^2
Metres unit cancels out so we are left with s^2
10.204s^2 = t^2
Square root both sides to cancel out square
t = 3.19 s
5 0
3 years ago
Read 2 more answers
A stone thrown horizontally from a height of 5.72 m hits the ground at a distance of 13.30 m. Calculate the initial speed of the
kakasveta [241]

Answer:

initial velocity=12.31 m/s

Final speed= 16.234 m/s

Explanation:

Given Data

height=5.72 m

distance=13.30 m

To Find

Initial Speed=?

Solution

Use the following equation to determine the time of the stone is falling.  

d = vi ×t   ½ ×9.8 × t²

Where  

d = 5.72m and vi = 0 m/s

so  

5.72 = ½× 9.8 ×t²

t = √(5.72 ÷ 4.9)

t=1.08 seconds

To determine the initial horizontal velocity use the following equation.

d = v×t

13.30 = v ×1.08

v = 13.30 ÷ 1.08

v=12.31 m/s

To determine stone’s final vertical velocity use the following equation

vf = vi+9.8×t............vi=0 m/s

vf = 9.8×1.08

vf= 10.584 m/s

To determine stone’s final speed use the following equation  

Final speed = √[Horizontal velocity²+Final vertical velocity²]

Final speed = √{(12.31 m/s)²+(10.584 m/s)²}

Final speed= 16.234 m/s

3 0
4 years ago
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