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2 years ago

what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?

Physics

2 answers:

Reil [10]2 years ago

3 0

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

Sloan [31]2 years ago

3 0

Answer: 160N

Explanation: Fr = coefficient x mass x acceleration due to gravity

= 0.2x80x10=160N

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3 years ago

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3 years ago

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2) for tungsten T = 2500 K

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3) for heated metal T = 1500 K

$\lambda_{max} = \dfrac{2898}{1500}$

$\lambda_{max} = 1.93 \mu_m$

4) for human skin T = 305 K

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5) for cryogenically cooled metal T = 60 K

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range of different spectrum

UV ----0.01-0.4

visible----0.4-0.7

infrared------0.7-100

for sun T = 5800

λ 0.01 0.4 0.7 100

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fractions

for UV = 0.125

for visible = 0.441-0.125 = 0.366

for infrared = 1 -0.491 = 0.509

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what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​

what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?