To solve the problem it is necessary to apply the concepts given in the kinematic equations of angular motion that include force, acceleration and work.
Torque in a body is defined as,
And in angular movement like
Where,
F= Force
d= Distance
I = Inertia
Acceleration Angular
PART A) For the given case we have the torque we have it in component mode, so the component in the X axis is the net for the calculation.
On the other hand we have the speed data expressed in RPM, as well
Acceleration can be calculated by
In the case of Inertia we know that it is equivalent to
Matching the two types of torque we have to,
PART B) The work performed would be calculated from the relationship between angular velocity and moment of inertia, that is,
Answer
The ways are;
• By commercializing low earth orbit
• By supporting water purification efforts worldwide
• By bringing space station ultrasound equipment on earth
• By improving eye surgery with space hardware
Explanation
There is a revolutionary commercial pathways that is currently opening access to space.For example, NASA is purchasing commercial cargo resupply to space station which enable U.S business to develop a competition in selling services to others while freeing NASA resources for deep space exploration. Using technology developed in space, the Water Security Corporation has deployed systems using NASA water-processing technology to ensure drinkable water availability for human survival. Medical care in remote regions is now facilitated by use of small ultrasound units, tele-medicine and remote guided methods similar to those used in space. The Eye Tracking Device experiment has enable researchers to have an insight into corrective laser surgeries.
Answer:
a. F = 245 Newton.
b. Workdone = 392 Joules.
c. Power = 196 Watts
Explanation:
Given the following data;
Mass = 25kg
Distance = 1.6m
Time = 2secs
a. To find the force needed to lift the mass (in N );
Force = mass * acceleration
We know that acceleration due to gravity is equal to 9.8
F = 25*9.8
F = 245N
b. To find the work done by the student (in J);
Workdone = force * distance
Workdone = 245 * 1.6
Workdone = 392 Joules.
c. To find the power exerted by the student (in W);
Power = workdone/time
Power = 392/2
Power = 196 Watts.
Answer:
1,600 to 1,700 kilocalories per day
Explanation:
