All categories

2 years ago

what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?

Physics

2 answers:

Reil [10]2 years ago

3 0

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

Sloan [31]2 years ago

3 0

Answer: 160N

Explanation: Fr = coefficient x mass x acceleration due to gravity

= 0.2x80x10=160N

You might be interested in

What kind of units as force measured by

Readme [11.4K]

Answer:

Newtons

Explanation:

5 0

3 years ago

Read 2 more answers

Please help will mark Brainliest the

VLD [36.1K]

Answer: 100 units

Explanation:

4 0

2 years ago

Isaac Newton was an English physicist who lived in the mid 1600s to the early 1700s. Newton stated that all objects are attracte

NISA [10]

Answer:

both staments are examples of scientfic laws

Explanation:

idk

6 0

2 years ago

Read 2 more answers

A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5m/s2 for 4s. After t

Pavlova-9 [17]

Taking right movement to be positive means leftward movement is negative.
Hence we have a deceleration of
$a = - 2.5 {ms}^{ - 2}$

$t = 4s$
$v = 3.0 {ms}^{ - 1}$
Using this 'suvat' equation
$v = u + at$
we can determine the initial velocity

$3.0= u + -2.5(4)$

$3.0+2.5(4)=u$

$13.0 = u$

Hence the initial velocity is 13.0 meters per seconds

3 0

3 years ago

Read 2 more answers

A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia

Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0

2 years ago

what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​

what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?