what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?

Physics

2 answers:

Reil [10]2 years ago

3 0

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

Sloan [31]2 years ago

3 0

Answer: 160N

Explanation: Fr = coefficient x mass x acceleration due to gravity

= 0.2x80x10=160N

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