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hjlf
2 years ago
13

What is the difference between the spectrum of an incandescent solid and the spectrum of an incandescent gas?

Physics
1 answer:
Nutka1998 [239]2 years ago
6 0

Answer:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

Explanation:

Materials when heated emit a continuous spectrum with all wavelengths.

Hot gas gases emit a spectrum that depends on the transitions between atomic states, therefore it is a discrete spectrum.

When reviewing the answers, the correct one is:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

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What are two things that determine our traits? If someone could answer asap, that would be awesome!
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In thinking about inherited traits, geneticists use two important words: genotype and phenotype. Genotype refers to the genes an organism inherits from its parents and phenotype refers to the observable characteristics of an organism: how it develops, looks, reacts and behaves. An inherited trait refers to a phenotypic characteristic, for example flower color, length of gestation or ability to metabolize cellulose. All traits have a genetic basis.
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3 years ago
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A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g).
qaws [65]

To solve this problem, let us recall that the formula for gases assuming ideal behaviour is given as:

rms = sqrt (3 R T / M)

where

R = gas constant = 8.314 Pa m^3 / mol K

T = temperature

M = molar mass

Now we get the ratios of rms of Argon (1) to hydrogen (2):

rms1 / rms2 = sqrt (3 R T1 / M1) / sqrt (3 R T2 / M2)

or

rms1 / rms2 = sqrt ((T1 / M1) / (T2 / M2))

rms1 / rms2 = sqrt (T1 M2 / T2 M1)

Since T1 = 4 T2

rms1 / rms2 = sqrt (4 T2 M2 / T2 M1)

rms1 / rms2 = sqrt (4 M2 / M1)

and M2 = 2 while M1 = 40

rms1 / rms2 = sqrt (4 * 2 / 40)

rms1 / rms2 = 0.447

 

Therefore the ratio of rms is:

<span>rms_Argon / rms_Hydrogen = 0.45</span>

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3 years ago
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A 0.73-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar
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Answer:

A)  B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West

Explanation:

A) For this exercise we must use the expression of Faraday's law for a moving body

            fem = -  \frac{d \phi }{dt}

            fem = - \frac{d (B l y}{dt}= - B l v- d (B l y) / dt = - B lv

            B = - \frac{fem}{l \ v}

we calculate

             B = - 7.9 10⁻⁴ /(0.73 20)

             B = 5.4 10⁻⁵ T

B) to determine which side of the bar is positive, we must use the right hand rule

the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.

Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West

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3 years ago
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