Question

EXAMPLE 11 Show that the points (1,-1),(5,2) and (9,5) are collinear​

Answer 1

Step-by-step explanation:

Hey, there!!!

Your question is about showing the points A(1,-1), B(5,2) and C(9,5) as a collinear point.

We generally slope to find weather the points are collinear or not.

So, let's find slope for AB.

$slope(m) = \frac{y2 - y1}{x2 - x1}$

$slope = \frac{2 + 1}{5 - 1}$

Therefore, slope of AB = 3/4.

Now, slope of BC.

$slope(m) = \frac{y2 - y1}{x2 - x1}$

$slope \: (m) = \frac{5 - 2}{9 - 5}$

Therefore, the slope is 3/4.

now, lastly slope of AC.

$slope(m) = \frac{y2 - y1}{x2 - x1}$

$slope(m) = \frac{5 + 1}{9 - 1}$

Therefore, the slope of AC is 3/4.

As all point have same slope. They are collinear point.

Hope it helps...

Answer 2

Answer:

see explanation

Step-by-step explanation:

They are collinear if the have the same slope

(2 - -1)/(5 - 1) = 3/4

(5 - 2)/(9 - 5) = 3/4

(5 - -1)/(9 - 1) = 6/8 = 3/4