C: It would follow a path perpendicular to the radius of its current orbit
When there is nothing to keep it going in circles, it will stop moving in circles around the sun and continue in a straight path. Think of it as a catapult. If the stick stops, the rock keeps flying straight at the speed and direction it was flung.
The answer to the question is A
Given that,
The acceleration of gravity is -9.8 m/s²
Initial velocity, u = 39.2 m/s
Time, t = 2 s
To find,
The final velocity of the shot.
Solution,
Let v is the final velocity of sling shot. Using first equation of motion to find it.
v = u +at
Here, a = -g
v = u-gt
v = (39.2)-(9.8)(2)
v = 19.6 m/s
So, its velocity after 2 seconds is 19.6 m/s.
Answer:
a = 6.4 [m/s²]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.
∑F = m*a
where:
∑F = sum of forces (horizontal force = 40 [N] and friction force = 8 [N])
m = mass of the block = 5 [kg]
a = acceleration [m/s²]
Now replacing:
![40-8=5*a\\32 = 5*a\\a=6.4[m/s^{2} ]](https://tex.z-dn.net/?f=40-8%3D5%2Aa%5C%5C32%20%3D%205%2Aa%5C%5Ca%3D6.4%5Bm%2Fs%5E%7B2%7D%20%5D)
Note: the sign of the friction force is negative since this force is acting against the movement of the block.
Answer:
The value 
Explanation:
From the question we are told that
The acceleration due to gravity is a = 2g
The maximum height is h= 39 m
Generally from the kinematic equation

Here u is the velocity of the ball at maximum height before it start falling and the value is 0 m/s
So



