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pogonyaev
3 years ago
13

Jeff is investigating factors that affect the growth rate of potted bean plants. Which of the following experimental variables w

ould not be relevant to his investigation?
A. the type of soil used
B. the amount of water given
C. the color of the pot
D. the amount of light exposure
Physics
2 answers:
Kipish [7]3 years ago
8 0
It would be C. the color of the pot. its pretty obvious that i would not effect the project.

aksik [14]3 years ago
5 0

Answer:

C. the color of the pot

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The answer to the question is A
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The acceleration of gravity is -9.8 m/s2. A sling shot fires a rock straight up into the air with a speed of +39.2 m/s. 1. what
Vanyuwa [196]

Given that,

The acceleration of gravity is -9.8 m/s²

Initial velocity, u = 39.2 m/s

Time, t = 2 s

To find,

The final velocity of the shot.

Solution,

Let v is the final velocity of sling shot. Using first equation of motion to find it.

v = u +at

Here, a = -g

v = u-gt

v = (39.2)-(9.8)(2)

v = 19.6 m/s

So, its velocity after 2 seconds is 19.6 m/s.

4 0
3 years ago
A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculat
valkas [14]

Answer:

a = 6.4 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

∑F = m*a

where:

∑F = sum of forces (horizontal force = 40 [N] and friction force = 8 [N])

m = mass of the block = 5 [kg]

a = acceleration [m/s²]

Now replacing:

40-8=5*a\\32 = 5*a\\a=6.4[m/s^{2} ]

Note: the sign of the friction force is negative since this force is acting against the movement of the block.

8 0
3 years ago
A ball is kicked on a planet the size of Earth but with twice the acceleration due to gravity. If the maximum height of the ball
USPshnik [31]

Answer:

The value t = 1.995 \  s

Explanation:

From the question we are told that

The acceleration due to gravity is a = 2g

The maximum height is h= 39 m

Generally from the kinematic equation

             s =  ut + \frac{1}{2} at^2

Here u  is the velocity of the ball at maximum height before it start falling and the value is  0 m/s

So

            39 =  0* t + \frac{1}{2} (2g)t^2

            39 = (9.8)t^2

            t =  \sqrt{3.9795918}

t = 1.995 \  s

3 0
4 years ago
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