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Katena32 [7]
2 years ago
8

Evaluate each scenario described to determine the direction of heat flow.

Chemistry
1 answer:
LuckyWell [14K]2 years ago
3 0

Answer: tap water to ice cube

Explanation:

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Viscous a chemical or physical property
Ahat [919]

Answer:

chemical

Explanation:

4 0
2 years ago
A ball is dropped from a height of 20 meters. At what height does the ball have a velocity of 10 meters/second?
musickatia [10]

Answer:

15m

Explanation:

vi = 0

vf = 10

a = -9.8

10^2 = 0 + 2(-9.8)(x2-x1) = -5.1

20-5.1 = 14.9m = 15m

3 0
2 years ago
A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom
Taya2010 [7]

Answer:

28/95 = 29.,5 % of Arsine decomposed

Explanation:A sample of gaseous arsine (AsH3) in a 460 mL flask at 332 Torr and 223 K, is heated to 437 K, at which temperature arsine decom- poses to solid arsenic and hydrogen gas. The flask is then cooled to 273 K, at which tem- perature the pressure in the flask is 488 Torr. What percentage of arsine molecules have de- composed?

Answer in units of %.

initial pressure 332 Torr initial volume 0.46 L initial temperature 223K

final pressure 488 Torr final volume 0.46 L final 273 K

Torr is 1/760 atm 332 torr = 0.437 atm 488 Torr =0.642 atm

PV = nRT so n=RT/PV

INITIAL n= 0.082 X 223/(0.437)(0.46) = 91 moles

final n= 0.082 X 273 / (.437)(488) = 105 moles

2AsH3----------> 2As + 3H2

x moles of Arsine decomposed to make 1.5 moles of H2

the final number of moles was

(91 -X)+ 1.5 X = 105 moles

91 + 0.5 X = 105

0.5 X = 14

X =28

CHECK

if 28 moles of Arsine , then the container would have

91 --28 + 1.5(28) = 91 +14 =105 check

so 28/95 = 29.,5 % of Arsine decomposed

Your answer

(quit)

polyalchemVirtuoso

Answer:

Explanation:

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4 0
2 years ago
What is the molality of a solution when 0.50 moles glucose is dissolved in 750 g of water?
xxMikexx [17]

Answer:

0.67mol/Kg

Explanation:

The following were obtained from the question:

Mole of solute = 0.50mol

Mass of solvent = 750g = 750/1000 = 0.75Kg

Molality =?

Molality = mole of solute /mass of solvent

Molality = 0.5/0.75

Molality = 0.67mol/Kg

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3 years ago
If a tank of gas contains 4 L of N O2 how many molecules are in it
Jobisdone [24]

but heres a way to solve it

An athlete takes a deep breath, inhaling 1.85 L of air at 21°C and 754 mm Hg.

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RT

h=

=

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