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Helen [10]
3 years ago
13

If one mole of rucl3·5h2o reacts with agno3 to produce two moles of agcl(s), how can the formula rucl3·5h2o be re-written to sho

w the proper coordination sphere?
Chemistry
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

The formula of the compound will be:[Ru(Cl)_1(H_2O)_5]Cl_2.

Explanation:

Coordination sphere is an array of ions or ligands around central atom or or an ion. Ions and ligands linked to central atom forms primary coordination sphere and ions or molecules linked to primary coordination sphere forms secondary coordination sphere.

Given: If one mole of RuCl_3.5H_2O reacts with AgNO_3 to produce two moles of AgCl precipitate.

This means that in primary coordination sphere there is a 1 chloride ion and 5 water molecules. And remaining 2 chloride ions present in secondary sphere which are available to react with silver ions of silver nitrate solution.

This why on reaction with silver nitrate 2 molecules or silver chloride are formed.

[Ru(Cl)_1(H_2O)_5]Cl_2+2AgNO_3(aq)\rightarrow 2 AgCl(s)+[Ru(Cl)_1(H_2O)_5](NO_3)_2(aq)

The formula of the compound will be:[Ru(Cl)_1(H_2O)_5]Cl_2.

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Single displacement reaction

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e-lub [12.9K]

Answer:

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mariarad [96]

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The  molecular formula  of the  hydrocarbon is  C6H12


    <u><em>Explanation</em></u>

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<h3><u><em> </em></u>Empirical formula  calculation</h3>

 Step 1:  find  the  moles   CO2  and  H2O

moles =mass/molar mass

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moles of H2O = 2.70 g / 18 g/mol =  0.15  moles

Step 2: Find the moles  ratio  of Co2:H2O  by diving  each mole by smallest mole(0.15)

that  is  for  CO2 = 0.15/0.15  =1

              For H2O = 0.15/0.15 =1

therefore  the mole ratio  of Co2 : H2O = 1:1  which  implies that 1 mole of Co2  and 1  mole of H2O is  formed  during combustion reaction.


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In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

From information above the empirical formula is therefore = CH2


Molecular formula  calculation

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[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

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Answer:

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