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Bumek [7]
3 years ago
14

36g of KOH dissolved in 800mL of water. What is the molality of the solution?

Chemistry
1 answer:
Zanzabum3 years ago
6 0

Answer:

0.80m of KOH

Explanation:

Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.

In the problem, the solute is KOH and solvent is water.

Moles of 36g KOH -Molar mass: 56.1g/mol- are:

36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>

<em></em>

Now, as density of water is 1g/mL, mass of 800mL of water is:

800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>

<em></em>

Thus, molality is:

0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>

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To determine the temperature of the gas, we need to assume ideal gas to use the equation PV=nRT where P represents the pressure, V is the volume, n is the number of moles, T is the temperature and R is the universal gas constant. We calculate as follows:

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