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zysi [14]
3 years ago
15

A certain ore is 20.7% nickel by mass. How many kilograms of this ore would you need to dig up to have 70.0 g of nickel?

Chemistry
1 answer:
LenKa [72]3 years ago
6 0

Answer:

0.3382 kg

Explanation:

From the illustration:

<em>100g of the ore would contain 20.7 g of nickel by mass</em>. In order to obtain 70.0 g of nickel, the amount of the ore needed would be:

          100 x 70.0/20.7 = 338.16 g

According to conversion units:

<em>1 g = 0.001 kg</em>

Hence,

338.16 g = 338.16 x 0.001 = 0.3382 kg

<em>Therefore, </em><em>0.3382 kg</em><em> of the ore would be required in order to obtain 70.0 g of nickel.</em>

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Answer:

Yes

Explanation:

There is a difference between the homogeneous mixture of the hydrogen and the oxygen in a 2:1 ratio and the sample of the water vapor.

In the homogeneous mixture of the hydrogen and the oxygen which are present in the ratio, 2:1 , the elements are not chemically combined. They are explosive also as both shows their specific properties. They can be separated by physical means (Condensation, diffusion).

On the other hand, in water vapor, the two elements are chemically bonded in a specific mixture which cannot be separated via physical means. Water has its unique properties and they can be separated by chemical means only.

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Teo3 lewis structure
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what is the molarity of a solution that has 1.54 moles NaCI in a 3.7L solution. How do you prepare 50ml of 0.5 M of KCI from a s
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A vessel contained N2, Ar, He, and Ne. The total pressure in the vessel was 987 torr. The partial pressures of nitrogen, argon,
xz_007 [3.2K]

Answer:

The partial pressure of neon in the vessel was 239 torr.

Explanation:

In all cases involving gas mixtures, the total gas pressure is related to the partial pressures, that is, the pressures of the individual gaseous components of the mixture. Put simply, the partial pressure of a gas is the pressure it exerts on a mixture of gases.

Dalton's law states that the total pressure of a mixture of gases is equal to the sum of the pressures that each gas would exert if it were alone. Then:

PT= P1 + P2 + P3 + P4…+ Pn

where n is the amount of gases present in the mixture.

In this case:

PT=PN₂ + PAr + PHe + PNe

where:

  • PT= 987 torr
  • PN₂= 44 torr
  • PAr= 486 torr
  • PHe= 218 torr
  • PNe= ?

Replacing:

987 torr= 44 torr + 486 torr + 218 torr + PNe

Solving:

987 torr= 748 torr + PNe

PNe= 987 torr - 748 torr

PNe= 239 torr

<u><em>The partial pressure of neon in the vessel was 239 torr.</em></u>

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