A certain ore is 20.7% nickel by mass. How many kilograms of this ore would you need to dig up to have 70.0 g of nickel?
1 answer:
Answer:
0.3382 kg
Explanation:
From the illustration:
<em>100g of the ore would contain 20.7 g of nickel by mass</em>. In order to obtain 70.0 g of nickel, the amount of the ore needed would be:
100 x 70.0/20.7 = 338.16 g
According to conversion units:
<em>1 g = 0.001 kg</em>
Hence,
338.16 g = 338.16 x 0.001 = 0.3382 kg
<em>Therefore, </em><em>0.3382 kg</em><em> of the ore would be required in order to obtain 70.0 g of nickel.</em>
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