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zysi [14]
3 years ago
15

A certain ore is 20.7% nickel by mass. How many kilograms of this ore would you need to dig up to have 70.0 g of nickel?

Chemistry
1 answer:
LenKa [72]3 years ago
6 0

Answer:

0.3382 kg

Explanation:

From the illustration:

<em>100g of the ore would contain 20.7 g of nickel by mass</em>. In order to obtain 70.0 g of nickel, the amount of the ore needed would be:

          100 x 70.0/20.7 = 338.16 g

According to conversion units:

<em>1 g = 0.001 kg</em>

Hence,

338.16 g = 338.16 x 0.001 = 0.3382 kg

<em>Therefore, </em><em>0.3382 kg</em><em> of the ore would be required in order to obtain 70.0 g of nickel.</em>

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Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).

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m (mass) = ? 

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\boxed{\boxed{m = 437.84\:g}}\end{array}}\qquad\checkmark

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