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4 years ago

A solution that has a high concentration of hydrogen ions has what type of pH?

2 answers:

7 0

A solution that has a high concentration of hydrogen ions has a pH value of 2. This means, the solution is very acidic and if one were to calculate the concentration of hydrogen ions, using the formula:

pH = -log(H+)

Given the concentration it would be low.

Degger [83]4 years ago

5 0

Given information:

A solution with a high H+ ion concentration

To determine:

The nature of pH of such a solution

Explanation:

pH is a measure of the H+ ion concentration in a given solution. Lower the pH higher will be the H+ concentration and the solution is termed acidic. In contrast, if the pH is higher the H+ concentration will be lower and the solution is basic.

Mathematically,

pH = -log[H+]

[H+] = $10^{-pH}$

pH = 2; [H+] = 10⁻²M

pH = 7; [H+] = 10⁻⁷M

pH = 13; [H+] = 10⁻¹³M

pH = 14; [H+] = 10⁻¹⁴M

Ans: (a)

Thus, the highest concentration of H+ ions is for a solution of pH = 2

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3 years ago

Consider an amphoteric hydroxide, m(oh)2(s), where m is a generic metal. estimate the solubility of m(oh)2 in a solution buffere

Colt1911 [192]

Missing data in your question: (please check the attached photo)
from this balanced equation:
M(OH)2(s) ↔ M2+(aq) + 2OH-(aq) and when we have Ksp = 2x10^-16
∴Ksp = [M2+][OH]^2
2x10^-16 = [M2+][OH]^2
a) SO at PH = 7
∴POH = 14-PH = 14- 7 = 7
when POH = -㏒[OH]
7= -㏒[OH]
∴[OH] = 1x10^-7 m by substitution with this value in the Ksp formula,
∴[M2+] =Ksp /[OH]^2
= (2x10^-16)/(1x10^-7)^2
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b) at PH =10
when POH = 14- PH = 14-10 = 4
when POH = -㏒[OH-]
    4 = -㏒[OH-]
∴[OH] = 1x10^-4 ,by substitution with this value in the Ksp formula
[M2+] = Ksp/ [OH]^2
= 2x10^-16 / (1x10^-4)^2
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c) at PH= 14
when POH = 14-PH
= 14 - 14
= 0
when POH = -㏒[OH]
  0 = - ㏒[OH]
∴[OH] = 1 m
by substitution with this value in Ksp formula :
[M2+] = Ksp / [OH]^2
= (2x10^-16) / 1^2
= 2x10^-16 M

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4 years ago