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bogdanovich [222]
3 years ago
8

How can a scientific law be expressed as a mathematical equation?

Chemistry
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

A scientific law is a statement that can usually be expressed as a mathematical equation that describes an occurrence in nature. At the time a law is made there are no exceptions to the law. However, over time, conditions may be observed that make the law true only in certain conditions.

Explanation:

Morgarella [4.7K]3 years ago
3 0

Answer:

Turn it into a equation

Explanation:

Simple

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Give the ground-state electron configuration for silicon (SiSi) using noble-gas shorthand. Express your answer in condensed form
nydimaria [60]

Answer:

[Ne] 3s² 3p²

Explanation:

Silicon atoms have 14 electrons. The ground state electron configuration of ground state gaseous neutral silicon is 1s²2s²2p⁶3s²3p².

Using noble gas shorthand, the electronic configuration is reduced to;

[Ne] 3s² 3p². Ne s the nearest noble gas to silicon, Ne contains 8 electrons, this means there's still 4 more electrons to fill. The s orrbital can only hold 2, hence the reaing two is transferred to the p orbital.

5 0
3 years ago
Why does the melting of the polar ice caps facilitate the absorption of CO2 by ocean waters?​
Korvikt [17]

hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

⊱┈────────────────────────⊰

Answer:

The melting of the caps increases the concentration of CO2 in the water, making its absorption faster.

⊱┈────────────────────────⊰

Explanation:

<h2><u>CO2 absorption</u><u> </u></h2>

The polar caps of our planet have in their composition several elements, among them the CO2 that is absorbed by the atmosphere. Cold waters, which are present in the Arctic, have an easier time absorbing CO2 compared to other waters.

When glaciers melt, the CO2 that is present in the mixture is dissolved in the ocean, increasing its concentration. The cold waters that came from the ice caps increase the absorption of CO2.

Learn more about natural methods remove CO2 from the atmosphere in:

brainly.com/question/14323197

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4 0
1 year ago
A student reacted NiS2 (MM = 122.83 g/mol) with O2 (MM=32.00 g/mol) to make SO2 (MM=64.07 g/mol) according to this balanced equa
Ilya [14]

Answer:

Percentage yield = 0.49 × 10² %

Explanation:

Given data:

Actual yield of SO₂ = 4.309 ×10² g

Theoretical yield of SO₂ = 8.78 ×10² g

Percentage yield = ?

Solution:

Chemical equation:

2NiS₂ + 5O₂ → 2NiO + 4SO₂

Percentage yield:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 4.309 ×10² g  / 8.78 ×10² g  × 100

Percentage yield = 0.491 × 100

Percentage yield = 49.1%

In scientific notation:

Percentage yield = 0.49 × 10² %

5 0
3 years ago
What is the molecular formula of a compound with the empirical formula
ipn [44]

Answer:  C_2H_2O_2

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula is CHO

The empirical weight of CHO = 1(12)+1(1)+1(16)= 29 g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula:

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{60}{29}=2

The molecular formula will be=2\times CHO=C_2H_2O_2

Thus molecular formula will be C_2H_2O_2

5 0
3 years ago
Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
3 years ago
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