Select the molecule where free rotation around one or more bonds is not possible. Group of answer choices N2H4 C2Cl4 NH3 C2H6 CC
1 answer:
Answer:
C₂Cl₄
Explanation:
To know if free rotation around a bond in a compound is possible, we need to see the structure of the compound (picture in attachment).
In single bonds, which are formed by σ bonds, the atoms are not fixed in a single position, and free rotation is permitted.
Double and triple bonds are formed by a σ bond and one or two π bonds, respectively. These bonds do not allow rotation, since it is not possible to twist the ends without breaking the π bond.
The chloroethylene (C₂Cl₄) has two carbons with an sp2-sp2 hybridization, they are bonded together by a double bond. <u>Free rotation on this bond is not possible, because six atoms, including the carbon atoms, doubly bonded and the four chlorine atoms bonded to them, must be on the same plane. </u>
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See the image below.
An excited electron is in a <em>high-energy state</em>.
When it drops to the lower-level ground state, it must get rid of this excess energy by <em>emitting it</em> as a quantum of light.
<u>Answer:</u> The beta-particle is being released in the reaction and the nucleus is changing from to nitrogen.
<u>Explanation:</u>
Carbon-14 undergoes a radioactive decay by the process of beta-minus decay.
In beta-minus decay, a neutron gets converted to a proton and an electron.
The equation for the beta-minus decay of carbon-14 follows the reaction:
In this reaction beta-particle is being released carrying -1 charge. Another name for this particle is known as electron.
In this decay process, the nucleus is changing from carbon to nitrogen. The property of the nucleus is changing completely as number of protons is getting increased.