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3 years ago

You are using a trandsducer with poor elevation resolution. what problem will most likely be encountered as a result?

Physics

2 answers:

Gnoma [55]3 years ago

6 0

Answer:

Inability to clearly demonstrate small cystic structures

Explanation:

Ultrasonic imaging is an integral and routine procedure in many medical applications. An increased awareness of the need for quality assurance in this field has led to numerous tests being proposed. Due to the complexity of the problem, the tests directly measuring the important parameters of resolution and contrast of low-echoic structures are not unified, often more qualitative than quantitative, and are performed at large periodic intervals. Uniform sensitivity of an array transducer is a necessary but insufficient requirement for imaging quality of an ultrasound probe. Good probe uniformity should in no way be confused with meaning the ultrasound probe is working as it should.

Results :

The 3-D view shows alternating orthogonal profiles. The lateral profile is determined at a single lateral position. To allow extrapolation of the result, scanner uniformity is required.

Uniformity will not work with phased arrays. As they need increased phase shifts for larger angles, side lobe generation increases at those angles, requiring additional measurements to check the respective quality reduction. For all other cases, a single 3D acquisition provides the complete information. The profiles can be plotted in 2D or 3D views.

As the beam profile changes only gradually between the single filaments, it is possible to interpolate the values between two successive points. Creating a grey-scale image using these interpolations provides an improved visualisation of the side lobes .

Alenkasestr [34]3 years ago

6 0

Answer:

it won't be easy to demonstrate small crystic structure.

Explanation:

TRANSDUCER is an electronic used to convert energy from one form to another. Common Examples of transducers are thermometer, antenna, light bulbs and loudspeakers.

An important to consider in transducers are their efficiency. Transducers efficiency can be defined as the ratio of power output to total power input. Its mathematical expression is given below;

Transducer efficiency,E= power output,PO/ total power input.

NB: the efficiency of transducers ranges from zero to one and no transducer is 100 percent efficient.

When one is using a trandsducer with poor elevation resolution, the problem it will cause is that it won't be easy to demonstrate small crystic structure.

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A straight vertical wire carries a current of 1.0 A into the page in a region where the magnetic field strength is 0.60 T. What

Advocard [28]

Answer:

force on the wire of section cm will be $6\times 10^{-3}N$

Direction of force on the wire will be in south direction

Explanation:

We have given current in the wire i = 1 A

Magnetic field strength B = 0.6 T

We have to find the force on 1 cm section of the wire so l = 1 cm = 0.01 m

Force on the wire containing current is equal to

$F=iBL$

$F=1\times 0.6\times 0.01=6\times 10^{-3}N$

So force on the wire of section cm will be $6\times 10^{-3}N$

Direction of force on the wire will be in south direction

5 0

3 years ago

The student quickly discovers that placing the marshmallow over the flame is more effective than heating the marshmallow on the

ANEK [815]

Answer:

The answer is convection.

Explanation:

There are three types of heat transfer: conduction, convection and radiation.

Conduction occurs when two objects touch each other and transfer heat.

Convection occurs when an object heats its surrounding fluid (like air, or water) and, since the hot fluids are less dense than the cold ones, they go up. So convection is a type of heat transfer that usually goes from down to up.

Radiation occurs when objects emanate heat in the form of electromagnetic waves that propagates in all directions.

So in this case, when the marshmallow is above the fire, it is exposed to convection, which does not occur when it is on the side of the fire.

4 0

4 years ago

Which process produces the energy radiated by the star when it becomes a main sequence star?

inysia [295]

The process that produces the energy radiated by stars is nuclear fusion in the core.
For a star on the main sequence, it's the fusion of hydrogen nuclei into helium.

8 0

4 years ago

. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in

kupik [55]

Answer:

Explanation:

The position is $r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}$ .

The velocity is the first time-derivative of r(t).

$v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}$

The acceleration is the first time-derivative of the velocity.

$a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}$

Since a(t) does not have the variable t, it is constant. Hence, at any time,

$a = -16\hat{j}$

Its magnitude is 16 m/s².

4 0

3 years ago

Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2

Tatiana [17]

You can reason it out like this:

-- The car starts from rest, and goes 8 m/s faster every second.

-- After 30 seconds, it's going (30 x 8) = 240 m/s.

-- Its average speed during that 30 sec is (1/2) (0 + 240) = 120 m/s

-- Distance covered in 30 sec at an average speed of 120 m/s

   = 3,600 meters .
___________________________________

The formula that has all of this in it is the formula for
distance covered when accelerating from rest:

   Distance = (1/2) · (acceleration) · (time)²

   = (1/2) · (8 m/s²)    · (30 sec)²

   = (4 m/s²) · (900 sec²)

   = 3600 meters.

_________________________________

When you translate these numbers into units for which
we have an intuitive feeling, you find that this problem is
quite bogus, but entertaining nonetheless.

When the light turns green, Andy mashes the pedal to the metal
and covers almost 2.25 miles in 30 seconds.

How does he do that ?

By accelerating at 8 m/s². That's about 0.82 G !

He does zero to 60 mph in 3.4 seconds, and at the end
of the 30 seconds, he's moving at 534 mph !

He doesn't need to worry about getting a speeding ticket.
Police cars and helicopters can't go that fast, and his local
police department doesn't have a jet fighter plane to chase
cars with.

3 0

3 years ago