When horizontal force is applied on block then as per Newton's II law we will have
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
![10 = m(5.3)](https://tex.z-dn.net/?f=10%20%3D%20m%285.3%29)
so here mass will be
![m = 1.89 kg](https://tex.z-dn.net/?f=m%20%3D%201.89%20kg)
now on same block F = 5 N is applied on surface of Moon
so on surface on moon we will have
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
![5 = 1.89 a](https://tex.z-dn.net/?f=5%20%3D%201.89%20a)
![a = 2.65 m/s^2](https://tex.z-dn.net/?f=a%20%3D%202.65%20m%2Fs%5E2)
so above is acceleration on surface of moon
Answer:
The average force exerted by the person on the box is 20 N.
Explanation:
Given that,
Impulse applied to the box, m = 5 kg-m/s
Time of contact of the person with the box is 0.25 seconds. We need to find the average force exerted by the person on the box. The impulse applied on an object is given by :
![J=F\times t](https://tex.z-dn.net/?f=J%3DF%5Ctimes%20t)
F is the average force exerted by the person on the box
![F=\dfrac{J}{t}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7BJ%7D%7Bt%7D)
![F=\dfrac{5\ kg-m/s}{0.25\ s}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B5%5C%20kg-m%2Fs%7D%7B0.25%5C%20s%7D)
F = 20 N
So, the average force exerted by the person on the box is 20 N. Hence, this is the required solution.
Temperature lower than absolute zero is not possible. Lower than absolute zero a gas contain negative pressure and volume which is not possible. temperature is the energy created by moving atoms absolute zero is a complete stand still you can make particles move to the end of the universe but the coldest temperature will be stuck at the point where atoms are motionless
hope that helped :)
(a) The work done by the applied force is 26.65 J.
(b) The work done by the normal force exerted by the table is 0.
(c) The work done by the force of gravity is 0.
(d) The work done by the net force on the block is 26.65 J.
<h3>
Work done by the applied force</h3>
W = Fdcosθ
W = 14 x 2.1 x cos25
W = 26.65 J
<h3>
Work done by the normal force</h3>
W = Fₙd
W = mg cosθ x d
W = (2.5 x 9.8) x cos(90) x 2.1
W = 0 J
<h3>Work done force of gravity</h3>
The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.
<h3> Work done by the net force on the block</h3>
∑W = 0 + 26.65 J = 26.65 J
Thus, the work done by the applied force is 26.65 J.
The work done by the normal force exerted by the table is 0.
The work done by the force of gravity is 0.
The work done by the net force on the block is 26.65 J.
Learn more about work done here: brainly.com/question/8119756
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