If you still need the answer it is B. 2 J
Answer:
<em>The power generated is = 5.33×10⁸ Watt. </em>
Explanation:
Power: Power can be defined as the time rate of doing work. The S.I unit of power is <em>Watt(W).</em>
<em>Mathematically,</em>
<em>Power (P) = Work done/time or Energy/time</em>
P = mgh/t............................... Equation 1
P = δgh............................. Equation 2
Where δ = fall rate, g = acceleration due to gravity, h = height.
<em>Given: </em>δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²
Substituting these values into equation 2
P = 1.1×10⁶×49.4×9.81
P = 533.08×10⁶
<em>P = 5.33×10⁸ Watt.</em>
<em>Thus the power generated is = 5.33×10⁸ Watt. </em>
Answer:
Explanation:
The variables we know and are given are:
time, t = 20s
Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)
We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:
I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)
If we substitute these values, we will get I as:
I = Q / t
I = 3x10^-6 / 20
I = 1.5x10^-7 A
Hope this helps!
We use the formula,
Here, h is the variable represents the height of the flare in feet when it returns to the sea so, h = 0 and u is the initial velocity of the flare, in feet per second and its value of 192 ft/sec.
Substituting these values in above equation, we get
.
Here, t= 0 neglect because it is the time when the flare is launched.
Thus, flare return to the sea in 12 s.
